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3 years ago

5

A car is purchase at $20000.The value of the car depreciates at 12.5% a year. What will the value of the car be to the nearest c

ent after 11 years

1 answer:

Rudik [331]3 years ago

6 0

Answer: $4603.82

Step-by-step explanation:

Given

The initial cost of a car is $P=\$20,000$

The rate of depreciation is $i=12.5\%$

Depreciated value after n years is given by

$\Rightarrow P(1-\frac{i}{100})^n\quad \text{where n=no. of years}$

Value after 11 years

$\Rightarrow 20,000(1-\frac{12.5}{100})^{11}\\\\\Rightarrow 20000(0.875)^{11}=\$4603.82$

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A table of values can be used to represent variables that are directly proportional.

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<em /> $L \to$ <em> Letters</em>

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$L = \frac{6.75}{0.045}$

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<u>When L = 1, we have:</u>

$C = 0.045L$

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<u>When L = 500, we have:</u>

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Solve for L

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Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Read more about proportions at:

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2 years ago

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