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Mashcka [7]
3 years ago
5

A car is purchase at $20000.The value of the car depreciates at 12.5% a year. What will the value of the car be to the nearest c

ent after 11 years
Mathematics
1 answer:
Rudik [331]3 years ago
6 0

Answer: $4603.82

Step-by-step explanation:

Given

The initial cost of a car is P=\$20,000

The rate of depreciation is i=12.5\%

Depreciated value after n years is given by

\Rightarrow P(1-\frac{i}{100})^n\quad \text{where n=no. of years}

Value after 11 years

\Rightarrow 20,000(1-\frac{12.5}{100})^{11}\\\\\Rightarrow 20000(0.875)^{11}=\$4603.82

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Schach [20]

Answer:

See below.

Step-by-step explanation:

ABC is an isosceles triangle with BA = BC.

That makes angles A and C congruent.

ABD is an isosceles triangle with AB = AD.

That makes angles ABD and ADB congruent.

Since m<ABD = 72 deg, then m<ADB = 72 deg.

Angles ADB and CDB are a linear pair which makes them supplementary.

m<ADB + m<BDC = 180 deg

72 deg + m<BDC = 180 deg

m<CDB = 108 deg

In triangle ABD, the sum of the measures of the angles is 180 deg.

m<A + m<ADB + m<ABD = 180 deg

m<A + 72 deg + 72 deg = 180 deg

m<A = 36 deg

m<C = 36 deg

In triangle BCD, the sum of the measures of the angles is 180 deg.

m<CBD + m<C + m<BDC = 180 deg

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m<CBD = 36 deg

In triangle CBD, angles C and CBD measure 36 deg making them congruent.

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2 years ago
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hram777 [196]
4 less than five times a number is -11:
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Answer:

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Step-by-step explanation:

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I hope this helps. =)
7 0
3 years ago
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