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jek_recluse [69]
2 years ago
6

Solve the equation for 3x-y = -3

Mathematics
1 answer:
S_A_V [24]2 years ago
8 0

Answer:

sln

3x-y=-3

3x-y=-3(make subject x)

3x=-3+y(divided by 3 both sides)

x=(-3+y) /3,x=-1+y /3

find y

3x-y=-3

-y=-3-3x(put the value of x)

-y=-3-3(-1+y/3)

-y=-6(-1+y/3)

-y=6+y/3

-y-y/3 =-3

-4y/3=-3(X by 3 both sides)

--4y=-6(divided by - 4 both sides)

y=1.5

find x

3x-y= -3 (put the value of y)

3x-1.5= -3

3x=-3+1.5

3x=-1.5(divided by 3 both sides)

x=-0. 5

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Can someone help me and explain? I will mark brainlest. ♡
Sedbober [7]

Answer:

p'(4) = -3

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Step-by-step explanation:

For p'(4):

p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)

p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3

For q'(8):

q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}

q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}

4 0
3 years ago
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Step-by-step explanation:

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2 years ago
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