All categories

3 years ago

Solve the equation for 3x-y = -3

Mathematics

1 answer:

S_A_V [24]3 years ago

8 0

Answer:

sln

3x-y=-3

3x-y=-3(make subject x)

3x=-3+y(divided by 3 both sides)

x=(-3+y) /3,x=-1+y /3

find y

3x-y=-3

-y=-3-3x(put the value of x)

-y=-3-3(-1+y/3)

-y=-6(-1+y/3)

-y=6+y/3

-y-y/3 =-3

-4y/3=-3(X by 3 both sides)

--4y=-6(divided by - 4 both sides)

y=1.5

find x

3x-y= -3 (put the value of y)

3x-1.5= -3

3x=-3+1.5

3x=-1.5(divided by 3 both sides)

x=-0. 5

You might be interested in

10. The sum of two numbers is 102. One number is three less than twice the other.

netineya [11]

Answer:

(2n -3) + n = 102

2n - 3 + n = 102

3n - 3 = 102

3n = 105

n = 35 (the first number)

SO...

The other number is (2 x 35) - 3 =

70 - 3 = 67 (the second number)

The numbers are 35 and 67.

35 + 67 = 102 CHECK!

7 0

3 years ago

56. How many tangent lines to the curve <img src="https://tex.z-dn.net/?f=y%3Dx%20%2F%28x%2B1%29" id="TexFormula1" title="y=x /(

PIT_PIT [208]

There are 2 tangent lines that pass through the point

$y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2$

and

$y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2$

Explanation:

Given:

$y=\frac{x}{x+1}$

The point-slope form of the equation of a line tells us that the form of the tangent lines must be:

$y=m(x-1)+2$ $[1]$

For the lines to be tangent to the curve, we must substitute the first derivative of the curve for $m$ :

$\frac{dy}{dx} =\frac{d(x)}{dx}(x+1)-x^\frac{d(x+1)}{dx} \\ \\$

$\frac{dy}{dx} =\frac{x+1-x}{(x+1)^2}$

$\frac{dy}{dx}= \frac{1}{(x+1)^2}$

$m=\frac{1}{(x+1)^2}$ $[2]$

Substitute equation [2] into equation [1]:

$y=\frac{x-1}{(x+1)^2}+2$ $[1.1]$

Because the line must touch the curve, we may substitute $y=\frac{x}{x+1}:$

$\frac{x}{x+1}=\frac{x-1}{(x+1)^2}+2$

Solve for x:

$x(x+1)=(x-1)+2(x+1)^2$

$x^2+x=x-1+2x^2+4x+2$

$x^2+4x+1$

$x\frac{-4±\sqrt{4^2-4(1)(1)} }{2(1)}$

$x=-2$ ± $\sqrt{3}$

$x=-2$ ± $\sqrt{3}$ <em> </em> $and$ $x=-2-\sqrt{3}$

There are 2 tangent lines.

$y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2$

and

$y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2$

8 0

3 years ago

Factor (z-5)(z+4)=52

Ipatiy [6.2K]

Good Afternoon! Here is your answer step by step!

Let's solve your equation step-by-step.

(z−5)(z+4)=52

Step 1: Simplify both sides of the equation.

z2−z−20=52

Step 2: Subtract 52 from both sides.

z2−z−20−52=52−52

z2−z−72=0

Step 3: Factor left side of equation.

(z+8)(z−9)=0

Step 4: Set factors equal to 0.

z+8=0 or z−9=0

z=−8 or z=9

Answer:

z=−8 or z=9

Have a blessed day! ❤

4 0

3 years ago

If the timer was started at the begining if the race would it affect the median. Why, not?

Ilia_Sergeevich [38]

Yeah It Would

~Hope This Helps :)
Need More Help With Question Just Inbox Me
Also Rate, Give Thanks, And Mark As Brainiliest.
Thank You ;)

7 0

3 years ago

Please help!! Thank you so much!!

Olenka [21]

Answer:

AC, AB, BC

Step-by-step explanation:

3x-13+2x-20+x+15=180

6x-18=180

6x=198

x=33

<a 86

<b 46

<c48

3 0

3 years ago