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mel-nik [20]
3 years ago
9

What is the solution to this system of equations? y=22x + 42

Mathematics
1 answer:
irga5000 [103]3 years ago
3 0

Answer:

y=22x+42

y/x=22+42

y/x=64

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If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?
eduard

Answer:

cos(\alpha+\beta)=-\frac{84}{85}

Step-by-step explanation:

we know that

cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)

Remember the identity

cos^{2} (x)+sin^2(x)=1

step 1

Find the value of sin(\alpha)

we have that

The angle alpha lie on the III Quadrant

so

The values of sine and cosine are negative

cos(\alpha)=-\frac{8}{17}

Find the value of sine

cos^{2} (\alpha)+sin^2(\alpha)=1

substitute

(-\frac{8}{17})^{2}+sin^2(\alpha)=1

sin^2(\alpha)=1-\frac{64}{289}

sin^2(\alpha)=\frac{225}{289}

sin(\alpha)=-\frac{15}{17}

step 2

Find the value of cos(\beta)

we have that

The angle beta lie on the IV Quadrant

so

The value of the cosine is positive and the value of the sine is negative

sin(\beta)=-\frac{4}{5}

Find the value of cosine

cos^{2} (\beta)+sin^2(\beta)=1

substitute

(-\frac{4}{5})^{2}+cos^2(\beta)=1

cos^2(\beta)=1-\frac{16}{25}

cos^2(\beta)=\frac{9}{25}

cos(\beta)=\frac{3}{5}

step 3

Find cos⁡ (α + β)

cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)

we have

cos(\alpha)=-\frac{8}{17}

sin(\alpha)=-\frac{15}{17}

sin(\beta)=-\frac{4}{5}

cos(\beta)=\frac{3}{5}

substitute

cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})

cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}

cos(\alpha+\beta)=-\frac{84}{85}

4 0
3 years ago
I’ll give brainliest, just help me please :)
Lemur [1.5K]

Answer:

V = 408    SA = 378

Step-by-step explanation:

To find the volume, you need to first find out the area and multiply it by overall length.

A = 1/2 (6)(8)

= 24

Volume = 24 x 17

= 408

Surface Area

SA = Front and Back + Right Side + Left Side + Bottom

= 2 [1/2 (6) (8)] + (17 x 10) + (3 x 8) + (17 x 8)

= 2 (24) + 170 + 24 + 136

= 48 + 170 + 24 + 136

= 378

6 0
3 years ago
What is the area of a regular hexagon with a side length of 4 m? Enter your answer in the box. Round only your final answer to t
hichkok12 [17]
The area of a hexagon is 
A= a^2 (3√3)/2
we replace a with 4
A=41.57
5 0
3 years ago
Read 2 more answers
Find the value of sin 0<br>cos(90°- 0) + cos 0 sin(90°-0)​
Step2247 [10]

Step-by-step explanation:

sin \theta \: cos(90 \degree - \theta) + cos \theta \: sin(90 \degree - \theta) \\  = sin(\theta + 90 \degree - \theta) \\  = sin(90 \degree)  \\  = 1

5 0
4 years ago
Need help please real fast will give brainlist
viktelen [127]

Answer:

-2

Step-by-step explanation:

Hope it helps

4 0
3 years ago
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