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3 years ago

Is algebra.

Mathematics

1 answer:

Ket [755]3 years ago

5 0

Answer:

$6(x-10)(x+9)$

Step-by-step explanation:

First, make A equal one by factoring out the greatest common factor, 6. This makes the new expression $6(x^{2} +x-90)$ . Then, factor the remaining polynomial by finding two numbers that multiply to -90 and add to 1. These two numbers are -10 and 9. So, add each term to x and then multiply to get the final answer, $6(x-10)(x+9)$ .

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Use the distance formula to find the distance, to the nearest tenth, from S(7, −1) to V(−1, 3).

34kurt

Answer: 8.9 units (choice C)

Explanation:

We plug $(x_1,y_1) = (7,-1) \text{ and } (x_2,y_2) = (-1,3)\\\\$ into the distance formula to get the following

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(7-(-1))^2 + (-1-3)^2}\\\\d = \sqrt{(7+1)^2 + (-1-3)^2}\\\\d = \sqrt{(8)^2 + (-4)^2}\\\\d = \sqrt{64 + 16}\\\\d = \sqrt{80}\\\\d \approx 8.94427\\\\d \approx 8.9\\\\$

4 0

2 years ago

Which mode of transportation did you choose? Why?

faust18 [17]

Answer:

land

Step-by-step explanation:

because,bus are more comfortable and easier other transportation are dangerous than land transportation ❤️

hope i helped u

8 0

3 years ago

Learning Task 3. Find the equation of the line. Do it in your notebook.

Wewaii [24]

Answer:

1) The equation of the line in slope-intercept form is $y = 5\cdot x +9$ . The equation of the line in standard form is $-5\cdot x + y = 9$ .

2) The equation of the line in slope-intercept form is $y = \frac{2}{5}\cdot x +\frac{14}{5}$ . The equation of the line in standard form is $-2\cdot x +5\cdot y = 14$ .

3) The equation of the line in slope-intercept form is $y = 3\cdot x +4$ . The equation of the line in standard form is $-3\cdot x +y = 4$ .

4) The equation of the line in slope-intercept form is $y = 2\cdot x + 6$ . The equation of the line in standard form is $-2\cdot x +y = 6$ .

5) The equation of the line in slope-intercept form is $y = \frac{5}{6}\cdot x -\frac{7}{6}$ . The equation of the line in standard from is $-5\cdot x + 6\cdot y = -7$ .

Step-by-step explanation:

1) We begin with the slope-intercept form and substitute all known values and calculate the y-intercept: ( $m = 5$ , $x = -1$ , $y = 4$ )

$4 = (5)\cdot (-1)+b$

$4 = -5 +b$

$b = 9$

The equation of the line in slope-intercept form is $y = 5\cdot x +9$ .

Then, we obtain the standard form by algebraic handling:

$-5\cdot x + y = 9$

The equation of the line in standard form is $-5\cdot x + y = 9$ .

2) We begin with a system of linear equations based on the slope-intercept form: ( $x_{1} = 3$ , $y_{1} = 4$ , $x_{2} = -2$ , $y_{2} = 2$ )

$3\cdot m + b = 4$ (Eq. 1)

$-2\cdot m + b = 2$ (Eq. 2)

From (Eq. 1), we find that:

$b = 4-3\cdot m$

And by substituting on (Eq. 2), we conclude that slope of the equation of the line is:

$-2\cdot m +4-3\cdot m = 2$

$-5\cdot m = -2$

$m = \frac{2}{5}$

And from (Eq. 1) we find that the y-Intercept is:

$b=4-3\cdot \left(\frac{2}{5} \right)$

$b = 4-\frac{6}{5}$

$b = \frac{14}{5}$

The equation of the line in slope-intercept form is $y = \frac{2}{5}\cdot x +\frac{14}{5}$ .

Then, we obtain the standard form by algebraic handling:

$-\frac{2}{5}\cdot x +y = \frac{14}{5}$

$-2\cdot x +5\cdot y = 14$

The equation of the line in standard form is $-2\cdot x +5\cdot y = 14$ .

3) By using the slope-intercept form, we obtain the equation of the line by direct substitution: ( $m = 3$ , $b = 4$ )

$y = 3\cdot x +4$

The equation of the line in slope-intercept form is $y = 3\cdot x +4$ .

Then, we obtain the standard form by algebraic handling:

$-3\cdot x +y = 4$

The equation of the line in standard form is $-3\cdot x +y = 4$ .

4) We begin with a system of linear equations based on the slope-intercept form: ( $x_{1} = -3$ , $y_{1} = 0$ , $x_{2} = 0$ , $y_{2} = 6$ )

$-3\cdot m + b = 0$ (Eq. 3)

$b = 6$ (Eq. 4)

By applying (Eq. 4) on (Eq. 3), we find that the slope of the equation of the line is:

$-3\cdot m+6 = 0$

$3\cdot m = 6$

$m = 2$

The equation of the line in slope-intercept form is $y = 2\cdot x + 6$ .

Then, we obtain the standard form by algebraic handling:

$-2\cdot x +y = 6$

The equation of the line in standard form is $-2\cdot x +y = 6$ .

5) We begin with a system of linear equations based on the slope-intercept form: ( $x_{1} = -1$ , $y_{1} = -2$ , $x_{2} = 5$ , $y_{2} = 3$ )

$-m+b = -2$ (Eq. 5)

$5\cdot m +b = 3$ (Eq. 6)

From (Eq. 5), we find that:

$b = -2+m$

And by substituting on (Eq. 6), we conclude that slope of the equation of the line is:

$5\cdot m -2+m = 3$

$6\cdot m = 5$

$m = \frac{5}{6}$

And from (Eq. 5) we find that the y-Intercept is:

$b = -2+\frac{5}{6}$

$b = -\frac{7}{6}$

The equation of the line in slope-intercept form is $y = \frac{5}{6}\cdot x -\frac{7}{6}$ .

Then, we obtain the standard form by algebraic handling:

$-\frac{5}{6}\cdot x +y =-\frac{7}{6}$

$-5\cdot x + 6\cdot y = -7$

The equation of the line in standard from is $-5\cdot x + 6\cdot y = -7$ .

6 0

2 years ago

Circumference and Area of a circle <br><br> #5 please

vlada-n [284]

Answer: the circumference is 25.13 and the area is 50.26 if rounding up then 50.27

Step-by-step explanation: to find circumference it is 2piR and to find the area it is piR^2

4 0

3 years ago

This graph shows transformations between f(x) = 10x and g(x) = a · 10x. Identify the following functions. p(x) = 4 · 10x q(x) =

wel

Anwers:

1. line A

2. line D

3. line B

4. line C

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.

Please have a look at the attached photo.

My answer:

Given the original function:

f(x) = 10x

and g(x) = a · 10x is the general from of all transformed functions from the above original function.

p(x) = 4 · 10x

The graph of this function is stretched vertically => line A

q(x) = –4 · 10x

The graph of this function is stretched vertically and is reflected through the x-asix => line D.

r(x) = (1/4) x 10x

The graph of this function is compressed vertically => line B

s(x) = (-1/4) x 10x

The graph of this function is compressed vertically and is reflected through the x-asix => line C

Hope it will find you well.

4 0

3 years ago

Read 2 more answers