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mariarad [96]
2 years ago
9

If John's dog weighs 16.23 lb how much would Jim's dog weigh​

Mathematics
2 answers:
Morgarella [4.7K]2 years ago
6 0

Answer:

It’s 5,41

Step-by-step explanation:

Hunter-Best [27]2 years ago
5 0
Jim's dog would be 5.41lb!!
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7 0
2 years ago
What is the value of f(-4)
WITCHER [35]

Answer:

7

Step-by-step explanation:

Substitute x = -4 :

f(-4) =  3 - (-4)

= 3 + 4

= 7

4 0
3 years ago
Find dy/dx by implicit differentiation.
kow [346]

dy/dx by implicit differentiation is cos(πx)/sin(πy)

<h3>How to find dy/dx by implicit differentiation?</h3>

Since we have the equation

(sin(πx) + cos(πy)⁸ = 17, to find dy/dx, we differentiate implicitly.

So, [(sin(πx) + cos(πy)⁸ = 17]

d[(sin(πx) + cos(πy)⁸]/dx = d17/dx

d[(sin(πx) + cos(πy)⁸]/dx = 0

Let sin(πx) + cos(πy) = u

So, du⁸/dx = 0

du⁸/du × du/dx = 0

Since,

  • du⁸/du = 8u⁷ and
  • du/dx = d[sin(πx) + cos(πy)]/dx

= dsin(πx)/dx + dcos(πy)/dx

= dsin(πx)/dx + (dcos(πy)/dy × dy/dx)

= πcos(πx) - πsin(πy) × dy/dx

So, du⁸/dx = 0

du⁸/du × du/dx = 0

8u⁷ × [ πcos(πx) - πsin(πy) × dy/dx] = 0

8[(sin(πx) + cos(πy)]⁷ ×  (πcos(πx) - πsin(πy) × dy/dx) = 0

Since 8[(sin(πx) + cos(πy)]⁷ ≠ 0

(πcos(πx) - πsin(πy) × dy/dx) = 0

πcos(πx) = πsin(πy) × dy/dx

dy/dx = πcos(πx)/πsin(πy)

dy/dx = cos(πx)/sin(πy)

So, dy/dx by implicit differentiation is cos(πx)/sin(πy)

Learn more about implicit differentiation here:

brainly.com/question/25081524

#SPJ1

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2 years ago
Find m angle QSRIf m angle TSQ=15x , m angle TSR=173^ , and m angle QSR=10x-2
Serggg [28]

{\color{red}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:꧁"Answer"꧂\:\:\: }}}}}}

\small\color{blak}{{\underline{\bold{ Find \:a X } } }  }

\small\color{black}{{\underline{\bold{173°=15z+10x-2 } } }  } \\  = 173 = 25x - 2 \\  =  - 25x =  - 2 - 173 \\  =  - 25x - 175 \\  = \small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: x=7\:\:\:\: }}}}

\small\color{blak}{{\underline{\bold{ Find\:a\:m

\small\color{blak}{{\underline{\bold{ 10(7)-2 } } }  }\\=70-2\\=\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: m

\Large\color{red}{{\underline{\mathfrak {{꧁"Carry\:on\: learning"꧂ }}}}}

7 0
2 years ago
A triangular flag has an area of 493 square meters and a height of 17 meters. What is the length of the base
ahrayia [7]

Answer:

\frac{984}{17} or around 57.88

Step-by-step explanation:

We can find the base length by using the formula for the area of a triangle.

A=\frac{bh}{2}

Plug in the values that we know, the area and the height, and solve for b.

493=\frac{17b}{2}

984=17b

b=\frac{984}{17}So the base is [tex]\frac{984}{17} or about 57.88 if you round to the nearest hundredth.

7 0
2 years ago
Read 2 more answers
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