I think this is because the molecules in the rock are so small. The rock is also a solid.
Air also affects evaporation,If a air pressure is high on the surface of a body of water,then the water will not evaporate easily.The pressure pushing down on the water makes its difficult for water to escape into the atmosphere as vapor... Temperature,of course,affects how quickly evaporation happens.
Cellular organization, Method of reproduction, Metabolism, Heredity, response to stimuli, homeostasis, adaptation to evolution, and growth and development,
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You will run and breathe heavily for a long period of time. is affecting your pH levels, Lowering the pH, making it more acidic.
- A. Lowering the pH, making it more acidic.
<h3>How does respiratory rate affect pH?</h3>
When it is respiratory, it occurs due to an increase in the amount of volatile acids in the body, which lead to an increase in pCO2. When it is metabolic, it occurs due to the accumulation of non-volatile acids, which lead to the loss (excessive consumption) of bases, mainly bicarbonate, causing a drop in pH.
With this information, we can conclude that By eliminating carbon dioxide during expiration, pulmonary ventilation reduces the acidity of the blood, helping it to maintain the desired alkalinity level.
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Plotting a graph of the mass or volume of the product created against time allows you to determine the reaction's pace. This is depicted for two reactions on the graph. The rate of reaction is inversely proportional to the gradient of the line; that is, the steeper the line, the higher the rate of reaction
<h3>What is Rate of reaction ?</h3>
The result is a straight line with a positive gradient on a graph of reaction rate against concentration (a graph showing proportionality).
- The half-life is constant in a concentration-time graph of first order. As a result, the period of time it takes for the concentration to decrease to 50% of its initial value is constant.
- It would be considered first order if you obtained a straight line with a negative slope. If you graph the inverse of the concentration for second order
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