Answer:
The correct answer choice is C.) 2 identical, diploid daughter cells.
<span>Is a group living things must be able to do all of the following except
A??</span>
Answer:
Option-A
Explanation:
Fertilization refers to the fusion of the male and female gamete to form the zygote.
When the fertilization occurs inside the organism through insemination then it is known as the internal fertilization and when it occurs outside the organism like observed in the amphibians when male and female gametes fuse in the water is known as external fertilization.
Both are different type of fertilization but share a similarity that is the formation of a single cell called the zygote which grows into the embryo by the mitotic division. The embryo later develops into the organism.
Thus, Option-A is correct.
Some of the conditions that must be met for a population or an allele to be in Hardy-Weinberg equilibrium are:
1. The population must be very large.
2. There must be no migration and population must be isolated.
3. There must be no mutations.
4. There must be random mating, which means there are no mating preferences.
So, a population will not be at Hardy-Weinberg Equilibrium if it is small, or there are mutations, which is not mentioned, but mutations are expected to occur. Also, although there is a large mountain, skunks can migrate to some other area of a woodland. So, probable mutations and migrations suggest that the population is not at <span>Hardy-Weinberg Equilibrium.</span>
The correct answer is Bolas spider. Bolas spiders usually spins a lasso to catch their preys. Instead of secreting the normal web which other spiders secrete, it secrete a stick capture net called bolas.
