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laila [671]
2 years ago
11

You are going to a private apple orchard to pick apples. There is a one-time entry fee

Mathematics
1 answer:
Jet001 [13]2 years ago
4 0

The one-time entry fee is $12.

In order to determine the one-time entry fee, two equations have to be formed from the information in the question:

x + 5y = 42 equation 1

x + 7y = 54  equation 2

Where:

x = one-time entry fee

y = cost to pick an apple per pound

In order to determine the one-time entry fee, take the following steps:

Multiply equation 1 by 7 and equation 2 by 5.

7x + 35y = 294 equation 3

5x + 35y = 270 equation 4

Subtract equation 4 from equation 3

2x =24

Divide both sides of the equation by 2

x = $12

To learn more, please check: brainly.com/question/23589883

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Inequalities are used to compare unequal expressions.

The actual comparison is:\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

The temperatures are given as:

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From the above list, we have:

\mathbf{Day \ 1=  -3.5F}

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\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

Using absolute values, the inequalities are:

\mathbf{|-3.5| < |5|} or \mathbf{|5| > |-3.5|}

Hence, the actual comparison is:

\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

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Anyone have the answer for this
sergiy2304 [10]

\huge\bold{Given:}

Length of the base = 16 km.

Length of the hypotenuse = 34 km. \huge\bold{To\:find:}

✎ The length of the missing leg ''a".

\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}

The length of the missing leg "a" is\boxed{30\:km}.

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

Using Pythagoras theorem, we have

({perpendicular})^{2}  +  ({base})^{2}  =  ({hypotenuse})^{2}  \\ ⇢ {a}^{2}  +  ({16 \: km})^{2}  =  ({34 \: km})^{2}  \\ ⇢ {a}^{2}   + 256 \:  {km}^{2}  = 1156 \:  {km}^{2}  \\ ⇢ {a}^{2}  = 1156 \:  {km}^{2}  - 256 \:  {km}^{2}  \\ ⇢ {a}^{2}  = 900 \:  {km}^{2}  \\ ⇢a \:  =  \sqrt{900  \: {km}^{2} }  \\ ⇢a =  \sqrt{30 \times 30 \:  {km}^{2} }  \\ ⇢a = 30 \: km

\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:"a"\:is\:30\:km.}

\huge\bold{To\:verify :}

( {30 \: km})^{2}  +  ({16 \: km})^{2}  =(  {34 \: km})^{2}  \\ ⇝900 \:  {km}^{2}  + 256 \:  {km}^{2}  = 1156 \:  {km}^{2}  \\⇝1156 \:  {km}^{2}  = 1156 \:  {km}^{2}   \\ ⇝L.H.S.=R. H. S

Hence verified. ✔

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

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Nikolay [14]
It will be 14 we calculated
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