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Lyrx [107]
3 years ago
7

Identify at least three tips you would give to people to stay safe on the Internet so that their information stays secure. Expla

in why these tips are useful.
Computers and Technology
2 answers:
Soloha48 [4]3 years ago
7 0

Answer:

1. Do not give away personal information such as your address, school you go to, or anything like that (obvious reasons

2. Do not share your passwords because people can hack into your things

3. Don't make guessable passwords such as Cookies, ILovePizza, Money

AveGali [126]3 years ago
4 0
1. Never give out your address, phone number, school name, etc.
This can lead to so many bad things. To protect yourself and others around you, don’t share your personal information to people you don’t know or trust.

2. Don’t add people on social media that you don’t know. I know a lot of people have public accounts and I’m not saying thats bad, but I am saying that you need to be careful on who’s adding you. There are a lot of creepy people out there.

3. Never open links people send you. If someone sends you a link online, it’s best to not open it. This opens up a whole new world for creeps to mess with you. They can track you, give you a virus or viruses. Never open random links that random people send you.
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The main advantage of a solid state drive is:
Sonbull [250]

the answer is they can store more information

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3 years ago
Part 1: Create an application that allows you to enter student data that consists of an ID number, first name, last name, and gr
aleksley [76]

<u>PART A</u>

import java.io.*;

import java.util.Scanner;

public class StudentsStanding {

   private static final double CUT_OFF = 2.0;

   public static void main(String[] args)

   {

       try {

           PrintWriter goodFile = new PrintWriter(new FileWriter("goodStanding.txt"));

           PrintWriter probationFile = new PrintWriter(new FileWriter("probation.txt"));

           char choice;

           String firstName,lastName;

           Scanner input = new Scanner(System.in);

           int id;

           double gradePoint;

           do {

               System.out.print("Enter student Id: ");

               id = input.nextInt();

               input.nextLine();

               System.out.print("Enter First name: ");

               firstName = input.nextLine();

               System.out.print("Enter last name: ");

               lastName = input.nextLine();

               System.out.print("Enter grade point: ");

               gradePoint = input.nextDouble();

               if(gradePoint<CUT_OFF)

                   probationFile.println(id+","+firstName+","+lastName+","+gradePoint);

               else

                   goodFile.println(id+","+firstName+","+lastName+","+gradePoint);

               System.out.print("Do you want to continue..(y/n): ");

               choice = input.next().toLowerCase().charAt(0);

           }while (choice!='n');

           //close the streams

           goodFile.close();

           probationFile.close();

       }

       catch (IOException ex)

       {

           System.err.println("IO Exception occurs...");

       }

   }

}

<u>PART 2</u>

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

public class StudentsStanding2 {

   private static final double CUT_OFF = 2.0;

   public static void main(String[] args)

   {

       String header = "ID\t"+"First Name"+"\t"+"Last Name"+"\t"+"Grade Point"+"\t"+"Exceeds/Fall\n";

       try {

           Scanner probationFile= new Scanner(new File("probation.txt"));

           Scanner goodFile = new Scanner(new File("goodStanding.txt"));

           System.out.println("Cut Off is: "+CUT_OFF);

           System.out.println(header);

           double point ,exceed;

           while (probationFile.hasNextLine())

           {

               String[] tokens = probationFile.nextLine().split(",");

               point = Double.parseDouble(tokens[3]);

               exceed = CUT_OFF-point;

               System.out.println(String.format("%4s %7s %10s %10s %10s",tokens[0],tokens[1],tokens[2],point,String.format("%.2f",exceed)));

           }

           //Close the stream

           probationFile.close();

           while (goodFile.hasNextLine())

           {

               String[] tokens = goodFile.nextLine().split(",");

               point = Double.parseDouble(tokens[3]);

               exceed = point - CUT_OFF;

               System.out.println(String.format("%4s %7s %10s %10s %10s",tokens[0],tokens[1],tokens[2],point,String.format("%.2f",exceed)));

           }

           goodFile.close();

       }

       catch (FileNotFoundException ex)

       {

           System.err.println("File not found!!!");

       }

   }

}

6 0
3 years ago
Discuss what repetitions structures are, and how they differ from the vectorization approaches we have previously studied in the
gogolik [260]

Repetition structures, or loops, are used when a program needs to repeatedly process one or more instructions until some condition is met, at which time the loop ends. Many programming tasks are repetitive, having little variation from one item to the next. Vectorized mathematical code appears more like the mathematical expressions found in textbooks, making the code easier to understand. That is the difference. Hope I could help you on Brainly.com!

6 0
3 years ago
What does it mean by MYRIAD of data?
pentagon [3]

Answer:

The term Myriad means an indefinitely large number of things. And when we say Myriad of data, we mean an indefinitely large amount of data like in Petabytes.

Explanation:

What it does implies is that you are dealing with a large amount of data. And hence we are dealing with something like bigData. And hence, technologies related to BigData are going to operate. And this term is used as a noun as well as an adjective when we talk about English. And hence, you can use it with "a" or without the "a" as well. It has been a part of reputable English and has been repeatedly used by top authors like Milton.

5 0
3 years ago
Which option ie an example of an html end tag
Kay [80]
Any end tag in HTML needs to look like this, the word body used in this example is one of the more important elements, but you can replace it to any real element in HTML:
i.e. </body>
8 0
3 years ago
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