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4 years ago

What is the smallest part of an element?

Physics

1 answer:

jolli1 [7]4 years ago

5 0

An atom. :) Good luck! The atom is the smallest particle in an element.

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To test the strength of a retainment wall designed to protect a nuclear reactor,

Hatshy [7]

Answer:

The speed of the F-4 Phantom upon impact is approximately 214.92 m/s

Explanation:

The given parameter of the motion of the F-4 Phantom jet aircraft are;

The mass of the F-4 phantom rocket, m₁ = 19,100 kg

The mass of the retaining wall, m₂ = 469,000 kg

The velocity of the combined mass of the wall and the F-4 after collision, v₃ = 8.41 m/s

The retainment wall was initially at rest, therefore, v₂ = 0 m/s

Let 'v₁', represent the speed of the F-4 Phantom upon impact

By the principle of conservation of linear momentum, we have;

m₁·v₁ + m₁·v₂ = m₁·v₃ + m₂·v₃ = (m₁ + m₂)·v₃

Plugging in the values, we have;

19,100 × v₁ + 469,000 × 0 = (19,100 + 469,000) × 8.41

∴ v₁ = (19,100 + 469,000) × 8.41/(19,100) = 214.917329843

v₁ ≈ 214.92

The speed of the F-4 Phantom upon impact, v₁ ≈ 214.92 m/s.

6 0

3 years ago

how do you get a snake out of your boot? This is very serious! I have a garden snake in my new boots.

stepan [7]

Take Off Your Boot, And Shake Your Boot

8 0

4 years ago

Read 2 more answers

What is the mass of a football player if they are running at 3.6 m/s with a momentum of 62.5kgm/s?

ioda

momentum = mass * velocity

62.5 = mass * 3.6

mass = 62.5/3.6

mass = 17.36 kg

7 0

4 years ago

Saturn is moving with uniform angular speed of 2πf along the circumference of it's orbit around the sun with radius R, having ce

Luda [366]

Answer:Sir haymo knows

Explanation:

he gave as homework

8 0

3 years ago

For general projectile motion with no air resistance, the vertical component of a projectile's acceleration For general projecti

Arte-miy333 [17]

Answer:

Rmains constant

Explanation:

The equation of the trajectory of a projectile motion is presented as follows;

$Y = x \cdot tan \theta -\dfrac{g \cdot x^2}{2 \cdot u^2 \cdot cos^2 \theta}$

The vertical componet of the prjectile motion is

y = (u·sinθ)·t - g·t²/2

Where;

θ = The angle with which the projectile is launched

x = The horizontal distance

u = The initial velocity of the projectile

g = The acceleration due to gravity = Constant

t = The time of motion

The acceleration acting on the projectile is the 'g' which is the constant acceleration due to gravity

Therefore, for general projectile motion with no air resistance, the vertical component of the projectile acceleration <em>remains constant</em>

6 0

3 years ago