*see attachment for the figure described
Answer:
5 units
Step-by-step explanation:
==>Given the figure attached below, let where FH and EG intercepted be K.
Since FH are midpoints of parallel lines, KE = KG = x.
Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.
Area of kite = ½ × d1 × d2
Where d1 = KH = 7
d2 = EG = KE + KG = x + x = 2x
Area of kite EFGH = 35
THUS:
35 = ½ × 7 × 2x
35 = 1 × 7 × x
35 = 7x
Divide both sides by 7
35/7 = x
x = 5
Answer:
L = 62.5cm; B = 30cm
Step-by-step explanation:
P = 2 (L+W): L=25cm; W=12cm
=2 (25+12)
=50+24
P = 74cm
For a congruent rectangle with P = 185cm
A: 74 = 2 (25 + 12)
B: 185 = 2( ? + ?)
Since A/B are congruent;
185/75 = 2.5
B = 2 (2.5* (25 + 12)
= 2 ( 62.5 + 30)
= 125 + 60
= 185
Hence, B: L = 62.5cm; B = 30cm
185cm = 2 (62.5 + 30)
Answer:
A. y = cos x
Step-by-step explanation:
The function that we see graphed has the point (0,1), this means whichever trig function f(x) it represents f(0) = 1.
Now, only the cosine function has the property that cos(0) = 1, thus choice A is the correct answer.
Answer:
I think that it is A or D
Step-by-step explanation:
<h3>
Answer: 15</h3>
=========================================================
Work Shown:
a = 9, b = 12 are the two legs of the right triangle
c = unknown is the hypotenuse
Apply the pythagorean theorem to find c
a^2 + b^2 = c^2
9^2 + 12^2 = c^2
81 + 144 = c^2
225 = c^2
c^2 = 225
c = sqrt(225)
c = 15
