Answer:
show me the question you need
Step-by-step explanation:
Answer:
21 students pass
Step-by-step explanation:
Firstly, you can set up the problem into an equation where the variable X would equal the number of students passing. You put X over the total number of students in the class, turning it into a fraction, then set it equal to the fraction
(which is 75% represented as a fraction).

The fraction
can be simplified, because 75 and 100 are both multiples of 25, so after canceling out the 25s you would be left with
.

Next, you use the process of cross multiplication which is essentially just multiplying the denominators of both fractions (which would be 28 and 4 in this case) to each side of the equation.

The denominators cancel out leaving you with a simple equation to simplify.


Finally, divide both sides by four in order to isolate the variable.

X = 21.
215 - 44.49 (I added the two deductions mentally) = 170.51
I see the percentages 2%, 1% and 3% add up to 6%
So we want 6% of 215 or .06 x 215 = $12.90
$170.51 - 12.90 = $157.61 net income.
State the domain of the relation R{(-3,3), (1,1), (0,2),(1,-4),(5,-1)} and then State the range of the relation R={(-3,3), (1,1)
harina [27]
The range is the Y value and the Domain is the X value.