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zimovet [89]
3 years ago
10

Can someone help me with this I’m very confused

Mathematics
1 answer:
shepuryov [24]3 years ago
5 0

Answer:

is this a question meant to evaluate you, such as a test, exam, quiz, or assessment?

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Len [333]
The answer to 9*9 is 81
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2/5 of 40 in fractional parts
Romashka [77]
Dividing 40 into fifths...
40 ÷ 5 = 8

Since 1/5 of 40 is 8, 2/5 of 40 is <u>16</u>.
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A factory packs 25 small shirts,30 medium shirtsand 15 large shirts in a box. If 550 boxes are packed with these shirts,how many
stealth61 [152]

Answer: the total number of shirts in all the boxes is 38500

Step-by-step explanation:

A factory packs 25 small shirts,30 medium shirt sand 15 large shirts in a box. This means that the total number of shirts that is packed into a box would be the sum of the small shirt, medium shirt and large shirt. It becomes

25 + 30 + 15 = 70

If 550 boxes are packed with these shirts, it means that the total number of shirts in all the boxes would be

550 × 70 = 38500

6 0
3 years ago
f a random sample of 300 adults is taken from the state of Colorado, where the rate of obesity is 19.8%, can we use the Normal a
Troyanec [42]

Answer:

Probability of at least 50 obese individuals in our sample is 0.92364 .

Step-by-step explanation:

We are given that a random sample of 300 adults is taken from the state of Colorado, where the rate of obesity is 19.8% .

Let X = Number of obese individuals

Firstly, X ~ Binom(n=300,p=0.198)

For approximating binomial distribution into normal distribution, firstly we have to calculate \mu and \sigma^{2} .

Mean of Normal distribution, \mu = n * p = 300 * 0.198 = 59.4

Variance of Normal distribution,\sigma^{2} = n * p * (1-p) = 300 *0.198 *0.802 = 47.64

So, now X ~ N(\mu = 59.4 , \sigma^{2} = 47.64)

The standard normal z score distribution is given by;

                     Z = \frac{X-\mu}{\sigma} ~ N(0,1)

So, probability of at least 50 obese individuals in our sample = P(X >= 50)

  P(X >= 50) = P(X > 49.5)  {using continuity correction}

  P(X > 49.5) = P( \frac{X-\mu}{\sigma} > \frac{49.5 - 59.4}{6.9} ) = P(Z > -1.43) = P(Z < 1.43) = 0.92364

Therefore, required probability is 0.92364 .

8 0
3 years ago
Using the numbers 15, 8, 5, 12 equals 17
Yuki888 [10]

Answer:

12+5=17

Step-by-step explanation:

4 0
3 years ago
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