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attashe74 [19]
3 years ago
13

Can someone help me?

Mathematics
1 answer:
Savatey [412]3 years ago
3 0
A 7x-2
b -x-6
C x+6
D 7x-2
E 7x^2-10x-8
F 9x^2-24x+16
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triangle ABC has coordinates A(4, 1), B(2, 3), and C(7, 5). If the triangle is rotated 270° counterclockwise about the origin, w
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Coordinates of a' would be (1,-4)

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PLEASE HURRY I HAVE A LITTLE BIT OF TIME TO TURN IT IN
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Answer:

4.25-5 minutes

Step-by-step explanation:

Its shown in the graph and table that the speed was 0 between those times.

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Show two different ways to factor -4x - 28​
horsena [70]

Step-by-step explanation:

-4x - 28

x = -28 + 4

x = -24

I HOPE THIS IS CORRECT IN ONLY THIS WAY SORRY IF IT IS WRONG

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3 years ago
Identify the variables, the constant, the coefficients, and the exponents in the algebraic expression: 5x + 3y^{2} + 4. (The 2 i
blsea [12.9K]
The variables are: x, y
The constant is: 4
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5 0
3 years ago
What set of reflections would carry trapezoid ABCD onto itself? (1 point) Trapezoid ABCD is shown. A is at negative 5, 1. B is a
amid [387]

Answer:

y=x, x axis,  y=x, y axis

Step-by-step explanation:

If a point A(x, y) is reflected along the y = x line, the new coordinates would be A'(y, x)

If a point A(x, y) is reflected across the x axis, the new coordinates would be A'(x, -y)

If a point A(x, y) is reflected along the y axis, the new coordinates would be A'(-x, y)

Firstly reflect Trapezoid ABCD along the y = x line to give:

A (-5, 1) ⇒ A'(1, -5). B (-4, 3) ⇒ B'(3, -4). C (-2, 3) ⇒C'(3, -2). D (-1, 1) ⇒ D'(1, -1)

Secondly reflect along the x axis to give:

A'(1, -5)⇒ A"(1,5). B'(3, -4)⇒ B"(3,4), C'(3, -2)⇒C"(3, 2), D'(1, -1) ⇒ D"(1, 1)

Thirdly reflect along the y = x line to give:

A"(1,5) ⇒ A"'(5, 1). B"(3,4) ⇒ B"'(4, 3). C"(3, 2) ⇒ C"'(2, 3). D"(1, 1) ⇒ D"'(1, 1)

Lastly reflect along the y axis to give:

A"'(5, 1) ⇒ A""(-5, 1), B"'(4, 3) ⇒ B""(-4, 3), C"'(2, 3) ⇒ C""(-2, 3), D"'(1, 1) ⇒ D""(-1.1)

6 0
3 years ago
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