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dusya [7]
2 years ago
11

HELP ASAPP!!!!!!!!! WHICH EQUATION FITS THE PATTERN IN THE TABLE THEN FIND THE MOSSING VALUES FOR N

Mathematics
1 answer:
valentina_108 [34]2 years ago
5 0

Answer:

The first answer is correct. 11n

 

Step-by-step explanation:

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For what value(s) of k will the relation not be a function
skelet666 [1.2K]

We are given two relations

(a)

Relation (R)

R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

k-8.3+2.4k=-\frac{3}{4} k

3.4k-8.3=-\frac{3}{4}k

3.4k\cdot \:10-8.3\cdot \:10=-\frac{3}{4}k\cdot \:10

4k-83=-\frac{15}{2}k

34k=-\frac{15}{2}k+83

\frac{83}{2}k=83

83k=166

k=2............Answer

(b)

S = {(2−|k+1| , 4), (−6, 7)}

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

2-|k+1|=-6

2-\left|k+1\right|-2=-6-2

-\left|k+1\right|=-8

\left|k+1\right|=8

Since, this is absolute function

so, we can break it into two parts

|f\left(k\right)|=a\quad \Rightarrow \:f\left(k\right)=-a\quad \mathrm{or}\quad \:f\left(k\right)=a

k+1=-8\quad \quad \mathrm{or}\quad \:\quad \:k+1=8

we get

k+1=-8\quad

k=-9

k+1=8\quad

k=7

so,

k=-9\quad \mathrm{or}\quad \:k=7...............Answer

5 0
3 years ago
12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
Gnesinka [82]

\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

  • RS || PQ,

  • RS = 3 cm,

  • PQ = 6 cm,

  • ar(∆ TRS) = 15 sq. cm

As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

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2 years ago
Michele correctly solved a quadratic equation using the quadratic formula as shown below.
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Jack and Diane participated in a weight loss program jack lost 6 pounds per Month for seven months Diane lost 4 pounds per month
Korolek [52]

Answer:

Step-by-step explanation:

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2 years ago
If anyone needs something to talk about or just needs somebody to talk too, You can comment and I'll reply as soon as possible.
vladimir2022 [97]

Answer:

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Step-by-step explanation:

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3 years ago
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