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castortr0y [4]
3 years ago
14

Mr.E.Terry, an engineer, runs a small business. The accounts for the firm are:

Mathematics
1 answer:
neonofarm [45]3 years ago
4 0

Journalizing the transactions in the accounts of Mr. E. Terry's firm are as follows:

Debit Rent Expense $450

Debit HST Recoverable $58.50

Credit Cash $508.50

Debit Supplies $76.55

Debit HST Recoverable $9.95

Credit Accounts Payable (Glen Printing) $86.50

Debit Accounts Receivable (J. Greenley) $250

Credit Service Revenue $221.24

Credit HST Payable $28.76

Debit Cash $200

Credit Accounts Receivable (R. Grieve) $200

Debit Cash $85.50

Credit Service Revenue $76.66

Credit HST $9.84

Debit Drawings, Terry $490

Credit Cash $490

Debit Bank Charges $25

Credit Cash $25

Debit Accounts Payable (Star Blueprinting) $500

Credit Cash $500

Debit Utilities Expense $200

Debit HST Recoverable $26

Credit Cash $226

Debit HST Payable $1,410

Credit HST Recoverable $890

Credit Cash $520

Data Analysis:

a. Rent Expense $450 HST Recoverable $58.50 Cash $508.50

b. Supplies $76.55 HST Recoverable $9.95 Accounts Payable (Glen Printing) $86.50

c. Accounts Receivable (J. Greenley) $250 Service Revenue $221.24 HST Payable $28.76

d. Cash $200 Accounts Receivable (R. Grieve) $200

e. Cash $85.50 Service Revenue $76.66 HST $9.84

f. Drawings, Terry $490 Cash $490

g. Bank Charges $25 Cash $25

h. Accounts Payable (Star Blueprinting) $500 Cash $500

i. Utilities Expense $200 HST Recoverable $26 Cash $226

j. HST Payable $1,410 HST Recoverable $890 Cash $520

Learn more: brainly.com/question/16889477

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How to find the perimeter of the triangle
Sliva [168]

Answer:

A. 26.2

Step-by-step explanation:

To find the perimeter of the triangle, you have to find the distances of all three lines and add them up.

<u>Line AB</u>

Let's start off by finding the distance of line AB.

We will use the formula, d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}.

Point A is (-2,5) and Point B is (4,-3).

To substitute the values, it will get to d = \sqrt{(4--2)^{2}+(-3-5)^{2}} which in other words is d = \sqrt{(4+2)^{2}+(-3-5)^{2}}.

Now we have to solve the parenthesis to get d = \sqrt{(6)^{2}+(-8)^{2}}.

Now we have to solve the exponents which would get to d = \sqrt{36+64}.

Now we have to simplify the square root to d = \sqrt{100}. In other words, that is d = 10.

Line AB = 10

<u>Line BC</u>

Now let's find the distance of line BC.

We will use the same formula, d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}.

Point B is (4,-3) and Point C is (0,-6).

To substitute the values, it will get to d = \sqrt{(0-4)^{2}+(-6--3)^{2}} which in other words is d = \sqrt{(0-4)^{2}+(-6+3)^{2}}.

Now we have to solve the parentheses to get d = \sqrt{(-4)^{2}+(-3)^{2}}.

Now we have to solve the exponents which would get to d = \sqrt{16+9}.

Now we have to simplify the square root to d = \sqrt{25}. In other words, that is d = 5.

Line BC = 5.

<u>Line AC</u>

Now let's fine the distance of line AC.

We will use the same formula, d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}.

Point A is (-2,5) and Point C is (0,-6).

To substitute the values, it will get to d = \sqrt{(0--2)^{2}+(-6-5)^{2}} which in other words is d = \sqrt{(0+2)^{2}+(-6-5)^{2}}.

Now we have to solve the parentheses to get d = \sqrt{(2)^{2}+(-11)^{2}}.

Now we have to solve the exponents which would get to d = \sqrt{4+121}.

Now we have to simplify the square root to d = \sqrt{125}. In other words, that is d = 5\sqrt{5}. To round that, d = 11.2.

Line AC = 11.2.

<u>Perimeter of Triangle ABC</u>

Perimeter of Triangle ABC = Line AB + Line BC + Line AC.

Perimeter of Triangle ABC = 10 + 5 + 11.2

Perimeter of Triangle ABC = 26.2

Hope this helped! If not, please let me know <3

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PLEASE HELP ASAP! WILL MARK BRANLIEST-
mafiozo [28]

Answer:

180

Step-by-step explanation:

8 0
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55.757 round to tenths
Leno4ka [110]
55.8 is the answer

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WINSTONCH [101]
Yes, because they have the same mesurements 

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Which line segment is an altitude of ΔVWY?
Paha777 [63]

Answer:

x

Step-by-step explanation:

just trust I know the x is the altitude

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