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expeople1 [14]
3 years ago
15

I need help with this ok thanks I’m having a real hard time BRANLIEST if you get thanks :)

Mathematics
2 answers:
patriot [66]3 years ago
4 0

Answer:

7+3=10

5+3=8

9+2=11

3+1=4

9+5=14

5+4=9

6+2=8

4+8=12

8+7=15

Brrunno [24]3 years ago
3 0

Answer:

1-11  2-4   3-14  4-9  5-8  6-12  7-15

Step-by-step explanation:plz mark brainliest

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A company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that
kondaur [170]

Answer:

Probability that the company wins project A or project B is 0.50.

Step-by-step explanation:

We are given that a company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that the company wins project B is 0.25.

Also, Winning project A and winning project B are independent events.

Let the Probability of winning project A = P(A) = 0.40

            Probability of winning project B = P(B) = 0.25

<u>Now, as we know that ;</u>

Probability that the company wins project A or project B = P(A \bigcup B)

              P(A \bigcup B) = P(A) + P(B) -  P(A \bigcap B)

So, we have to find the value of Probability of winning project A and B, i.e;

P(A \bigcap B)

<em>Since, we are given that Winning project A and winning project B are independent events which means when this condition is given then;</em>

                    P(A \bigcap B) = P(A) \times P(B)

                                    = 0.40 \times 0.25 = 0.10

Now, Probability that the company wins project A or project B is given by;

                 P(A \bigcup B) = P(A) + P(B) -  P(A \bigcap B)  

                                  = 0.40 + 0.25 - 0.10

                                  = 0.65 - 0.10 = 0.55

Hence, probability that the company wins project A or project B is 0.50.

3 0
3 years ago
I need some help with this one?
Elis [28]

Answer:

try 1 and 2 for supplementary

and 7 and 6 for vertical

Step-by-step explanation:

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Is anyone here connections academy 9th grade math 1?
mojhsa [17]
Yes, i am what do you need help with?

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