(c+3)-2c-(1-3c)=2
c+3-2c-1+3c=2
2c+2=2
2c=0
c=0
It would show the average time spent on the homework.
And the average distance between the mean and the lowest and highest numbers in the data.
Answer:
Step-by-step explanation:
h = √6 units
b = √9 units
A = b*h/2 = √6·√9 /2 = √(6·9)/2 = √(2·3·3·3)/2 = 3√3 /2 units ²≈ 2.6 units²
Step-by-step explanation:
i can't see ur question the pic is black can u resend
Start by reviewing your knowledge of natural logarithms. If we take the ln of both sides we get e^z=ln(1). Do the same thing again and wheel about the ln(ln(1)). There's going to be complex solutions, Wolfram Alpah gets them but let me know if you figure out how to do it?
