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Law Incorporation [45]
3 years ago
9

Find c, given that a + 18.2, B = 62, and C =48. Round answer to the nearest whole number. Do not use a decimal point or extra sp

aces in the answer or it will be marked incorrect
Mathematics
1 answer:
DanielleElmas [232]3 years ago
3 0

Answer:

c=14

Step-by-step explanation:

a = 18.2

\angle B=62^{\circ}

\angle C=48^{\circ}

\angle A=180-(62+48)=70^{\circ}

From sine rule we have

\dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}

\Rightarrow \dfrac{\sin A}{a}=\dfrac{\sin C}{c}

\Rightarrow c=\dfrac{\sin C}{\sin A}a

\Rightarrow c=\dfrac{\sin 48^{\circ}}{\sin 70^{\circ}}\times 18.2

\Rightarrow c=14.4\approx 14

\boldsymbol{\therefore c=14}.

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What is the approximate area of the shaded sector in the circle shown below
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Expand:<br> 4(5x+5) - 3(2x + 4)
aliina [53]

Answer:

14x + 8

Explanation:

⇒ 4(5x+5) - 3(2x + 4)

distribute inside parenthesis

⇒ 4(5x) + 4(5) - 3(2x) - 3(4)

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A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

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P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

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(4x + 3) + (-2x + 4)
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Answer:

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= 4x + 3 - 2x + 4         <em>combine like terms</em>

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