The machine was operated for 4.5 hours
A machine uses gasoline at a rate of 1/5 gallon per hour
The number of hours it will take the machine to use 9/10 gallon can be calculated as follows
1/5 = 1
9/10= x
cross multiply
1/5x= 9/10
0.2x= 0.9
x= 0.9/0.2
x= 4.5
Hence the machine was operated for 4.5 hours
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A. <u>False.</u> The range of 
is the set of values it can produce. In the table, produces values from 
to 
. However, the range of all real numbers is all rational numbers, basically from 
to 
, not just a few numbers in-between. So, the range of is not all real numbers.
B. <u>True.</u> Looking at the table, when 
, 
. This is another way of saying that 
, which is what B is saying.
C. <u>True.</u> The domain of is the set of values of 
that produce some output in . Looking at the table, all of the values listed on it are in the set 
, which is what C is saying.
D. <u>False.</u> Looking at the table, when 
, 
. This is another way of saying that 
, which is <em>not </em>what B is saying.
Speed of light in vacuum = 2.998 x 10^8 m/s
1m = 1/1000 km and 1s = 1/3600 hr
Speed of light in vacuum = (2.998 x 10^8 x (1/1000)
km) / (1/3600) hr
Speed of light in vacuum = 10.792 x 10^8 km/hr
Now
1km = 0.6213 mi
1hr = 60min
As Speed of light in vacuum = 10.792 x 10^8 km/hr
Speed of light in vacuum = 10.792 x 10^8 x (0.6213mi)
/ 60min
Speed of light in vacuum = 0.1117 x 10^8 mi/min
<span>Speed of light in vacuum = 11.17 x 10^6 mi/min</span>
Answer:
B=-2+5 collecting like terms
B=3 answer
