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2 years ago

The volume of a storage tank is 3,375 cubic meters. The storage tank is in the shape of a cube. What is the length of each side?

1 answer:

6 0

2,275 should be the length of each side.

Basically what you do is cut the cubic meters in half and subtract.

Have a great day!

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How Do You Write .0676767 In Scientific Notation?

evablogger [386]

6.8 x 10^-2

The scientific notation of 70, 030, 000. To find the scientific notation of this value 
1. We first move the period which separates the whole number from the decimal number which is located after the numbers of the given value.
2. We move it in the very recent order number which is seventy million, seven and zero. 
3. It becomes 7.003
4. Thus we count how many moves we did from the tens to the ten million order place. 
5. 7.003 x 10^7

4 0

3 years ago

The height h(n) of a bouncing ball is an exponential function of the number n of bounces.

Digiron [165]

Answer:

The height of a bouncing ball is defined by $h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$ .

Step-by-step explanation:

According to this statement, we need to derive the expression of the height of a bouncing ball, that is, a function of the number of bounces. The exponential expression of the bouncing ball is of the form:

$h = h_{o}\cdot r^{n-1}$ , $n \in \mathbb{N}$ , $0 < r < 1$ (1)

Where:

$h_{o}$ - Height reached by the ball on the first bounce, measured in feet.

$r$ - Decrease rate, no unit.

$n$ - Number of bounces, no unit.

$h$ - Height reached by the ball on the n-th bounce, measured in feet.

The decrease rate is the ratio between heights of two consecutive bounces, that is:

$r = \frac{h_{1}}{h_{o}}$ (2)

Where $h_{1}$ is the height reached by the ball on the second bounce, measured in feet.

If we know that $h_{o} = 6\,ft$ and $h_{1} = 4\,ft$ , then the expression for the height of the bouncing ball is:

$h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$

The height of a bouncing ball is defined by $h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$ .

5 0

3 years ago

Read 2 more answers

How do you find an area of a triangle when you just have two sides and an angle?

Olenka [21]

You have to use sin, cos, tan and find the length of the last side and other angles. Then you have to put an imaginary line down the middle and use the sin, cos, tan to find the height and then do 1/2 base times height.

5 0

3 years ago

Perform the indicated operations. give answers in simplified form. √9/25

tino4ka555 [31]

$\sqrt{\frac{9}{25}} = \frac{\sqrt{9}}{\sqrt{25}} = \frac{3}{5}$

8 0

3 years ago

In ΔBCD, \overline{BD} BD is extended through point D to point E, \text{m}\angle CDE = (9x-12)^{\circ}m∠CDE=(9x−12) ∘ , \text{m}

UNO [17]

Answer:

Angle BCD is 13 degrees

Step-by-step explanation:

Here, we want to find the measure of angle BCD

To get this, we need an appropriate diagram. The diagram can be seen in the attachment.

To find the value of BCD, we can use an important triangle theorem.

This is that the sum of opposite interior angles of a triangle equals the exterior angle.

Thus, we have that;

BCD + DBC = CDE

hence;

3x + 5 + 2x + 3 = 9x-12

5x + 8 = 9x -12

9x-5x = 8 + 12

4x = 20

x = 20/4

x = 5

So the measure of BCD will be 2(5) + 3 = 10 + 3 = 13

8 0

3 years ago