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ANTONII [103]
2 years ago
8

HELPPPP DUE SOOON ILL GIVE BRAINLESS PLS HELPPP

Mathematics
1 answer:
oee [108]2 years ago
6 0

The answer is 3/2


Find the slope of the line

M = y2-y1/ x2-x1

M=9-0 /6-0

M=9 divide 3 / 6 divide by 3

M= 3/2 cm/s

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Two consecutive positive integers have a product of 6. what are the integers
sergejj [24]

Hey there!

One way to do this is find all the factors of 6 and then see which pair fit the requirements.

The factors of 6 are 1, 2, 3, and 6. (Note: There can be negative factors, but I am going to leave them out since it is asking for positive integers.)

You can find them by asking if each number can go into 6.

1, 2, 3, and 6 all go into 6, while 4 and 5 do not.

The requirements we have is that they must be consecutive <u>and</u> have a product of 6.

Consecutive means right after one another.

The only numbers that fit this are 2 and 3.

2 x 3 = 6

Hope this helps!

6 0
2 years ago
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Pls help....................
PolarNik [594]
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6 0
2 years ago
Mary and Jane have $48 to share in the ratio 3:5. How much did each girl 2 points
zubka84 [21]

Answer:

Mary- $18

Jane- $30

Step-by-step explanation:

Add the numbers in the ratio together to get 8, and multiply 8 by the variable of x. Divide the total amount of money that both girls earned by 8. You will get x=6. Multiply 6 by 3 to get the amount of money Mary earned, which is 18, and multiply 6 by 5 to get the amount of money Jane earned, which is 30.

x(3+5) = $48

3x + 5x = $48

8x = $48

8x/8 = $48/8

x = $6

3($6):5($6) = $18:$30

4 0
2 years ago
Read 2 more answers
I feel like crying! why is math so hard???
Sladkaya [172]

Answer:

honestly wish math would just jump off the planet with that fancy ole brown necklace we call a rope.

4 0
2 years ago
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Write the equation in standard form for the circle with center (0, 9) passing through (0, 27/2)
sammy [17]

Given

coordinates of center= (0,9)

Circle passes through (0, 27/2)

Find

Equation of circle

Explanation

The equation of circle in standard form is

\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ (x-0)^2+(y-9)^2=r^2 \end{gathered}

We know the circle passes through (0,27/2), then

\begin{gathered} (0-0)^2+(\frac{27}{2}-9)^2=r^2 \\ r=4.5 \end{gathered}

So the equation in the standard form is

(x-0)^2+(y-9)^2=4.5^2

Final Answer

(x-0)^2+(y-9)^2=4.5^2
8 0
10 months ago
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