The y intercept is (0,-2)
That is the final answer to this question
42765
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
Answer:
Step-by-step explanation:
4/x + 4/(x²-9) = 3/(x - 3)
4 / x + 4 / [( x - 3) ( x + 3 )] = 3 / ( x - 3 ) / * x ( x - 3 ) ( x + 3 )
Restrictions : x ≠ 0, x ≠ - 3 , x ≠ 3;
4 ( x + 3 ) ( x - 3 ) + 4 x = 3 x ( x + 3 )
4 ( x² - 9 ) + 4 x = 3 x² + 9 x
4 x² - 36 + 4 x - 3 x² - 9 x = 0
x² - 5 x - 36 = 0
x² - 9 x + 4 x - 36 = 0
x ( x - 9 ) + 4 ( x - 9 ) = 0
( x - 9 ) ( x + 4 ) = 0
x - 9 = 0, or : x + 4 = 0
Answer:
x = 9, x = - 4
