Question

Item 5 Let f(x)=2 (3) x+1 +4 . The graph of f(x) is stretched vertically by a factor of 2 to form the graph of g(x) . What is the equation of g(x) g(x) ?

Answer 1

Answer:

$g(x)=4(3)^{x+1}+8$

Step-by-step explanation:

Given:

The original function is given as:

$f(x)=2(3)^{x+1}+4$

The above function is stretched vertically by a factor of 2 to form the graph of $g(x)$.

According to the rule of function transformations, when the graph of a function is stretched in the vertical direction by a factor of 'C', where, 'C' is a number greater than 1, then the function rule is given as:

$f(x)\to Cf(x)$

Therefore, the function is multiplied by a factor of 'C' to get the equation of the stretched function.

Here, the the value of 'C' is 2. So, the equation of $g(x)$ is given as:

$g(x)=2f(x)\\g(x)=2[2(3)^{x+1}+4]\\g(x)=4(3)^{x+1}+8$

Therefore, the equation of $g(x)$ is $g(x)=4(3)^{x+1}+8$.