90,000*0.12 =1,080
1,080*7=7,560
90,000+7,560=97,560
Answer :
no. of days used to repair 1250m of road = 5
no. of days used to repair 1m of road = 5/1250
no. of days used to repair 8000m of road (8*1000m ) = 5/1250*8000= 32 days
Answer:
A)
Step-by-step explanation:
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4 +5 = 9 and 12 + 3 =15 and there is more than this
hope I helped
