Given h(x) = -3x – 5, solve for x when h(x) = –2.

Mathematics

1 answer:

leva [86]3 years ago

5 0

-2=-3x -5
3=-3x
x=-1
i think that’s the correct answer if h(x) is -2 assuming its y

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pogonyaev

Answer:

<em>Second number line</em>

Step-by-step explanation:

<u>Intervals in the Number Line</u>

When representing real intervals in the number line, we use solid lines that start from the lower or upper limit and end in the final number. If there is no limit, then we use an arrow pointing to plus or minus infinity.

If the endpoint is included in the interval, we place a filled circle, if it's not included, we use a hollow circle.

We want to show the interval $x\geq 11$ , this means we must include the 11 and go up to positive infinity. The only number line with such characteristics is that on the second option.