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nevsk [136]
3 years ago
11

Hurry please help ASAP !!!

Mathematics
1 answer:
Kobotan [32]3 years ago
6 0

Answer:

vertical angles

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Identify the center and radius from the equation of the circle given below. x^2+y^2+121-20y=-10x
Tcecarenko [31]

Answer:

Center: (-5,10)

Radius: 2

Step-by-step explanation:

The equation of the circle in center-radius form is:

(x-h)^2+(y-k)^2=r^2

Where the point (h,k)  is the center of the circle and "r" is the radius.

Subtract 121 from both sides of the equation:

x^2+y^2+121-20y-121=-10x-121\\x^2+y^2-20y=-10x-121

Add 10x to both sides:

x^2+y^2-20y+10x=-10x-121+10x\\x^2+y^2-20y+10x=-121

Make two groups for variable "x" and variable "y":

(x^2+10x)+(y^2-20y)=-121

Complete the square:

Add (\frac{10}{2})^2=5^2 inside the parentheses of "x".

Add  (\frac{20}{2})^2=10^2  inside the parentheses of "y".

Add 5^2 and 10^2 to the right side of the equation.

Then:

(x^2+10x+5^2)+(y^2-20y+10^2)=-121+5^2+10^2\\(x^2+10x+5^2)+(y^2-20y+10^2)=4

Rewriting, you get that the equation of the circle in center-radius form is:

 (x+5)^2+(y-10)^2=2^2

You can observe that the radius of the circle is:

r=2

And the center is:

(h,k)=(-5,10)

6 0
3 years ago
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Equivalent expression to 3y+4-6y-2
olga55 [171]

Answer :   the answer is -3y + 2

3 0
4 years ago
Can somebody pls help me.. ​
ale4655 [162]
If you solve for the vertex of the function, you would get (-3, -1). So I think it would be x = -3 and the function’s maximum value would be -1. Hope this helps!! :)
8 0
3 years ago
How do you find the area of the shaded sector of the circle? The radius is 10in and the sector is 45 degrees
Step2247 [10]

Given:

Radius of the circle = 10 in

Central angle of the sector = 45 degrees

To find:

The area of the sector.

Solution:

Area of a sector is

A=\dfrac{\theta}{360^\circ}\pi r^2

Where, \theta is the central angle in degrees.

Putting r=10 and \theta=45^\circ, we get

A=\dfrac{45^\circ}{360^\circ}\pi (10)^2

A=\dfrac{1}{8}\pi (100)

A=12.5\pi

Therefore, the area of the sector is 12.5π sq. inches.

7 0
3 years ago
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