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Fantom [35]
3 years ago
5

What fraction would you use to find 66.66% of 72?

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0
I don't think you use a fraction. You multiply .6666 by 72 which equals 47.9952 or rounded 48. :)
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1/2 (x-4/5)=3/5
malfutka [58]
1/2x-2/5=3/5       (BTW I got 2/5 by reducing 4/10)
1/2x=7/5             (BTW I got 7/5 by moving 2/5 to the other side)
Then do 7/5 times 2 and you get 14/5

14/5

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6 0
3 years ago
Find x show ur work !!
Elis [28]

Answer:

x = 10

Step-by-step explanation:

A triangle's angles add up to 180 degrees, so 180-90 (the right angle) is 90 degrees. That means that

4x+6+3x+14 = 90. Then we simplify so

7x + 20 = 90. Then we can subtract 20 from each side so

7x = 70. Then, we find that

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4 0
3 years ago
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Plsss helpp mathhh and thank u if u answer
kompoz [17]

Answer:

a. 60 centimeters

b. 67 centimeters

Step-by-step explanation:

a.

12 × 4 = 48

(6 × 4) ÷ 2 = 12

48 + 12 = 60

b.

7 × 10 = 70

(2 × 3) ÷ 2 = 3

70 - 3 = 67

7 0
2 years ago
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
3 years ago
John wants to know the volume of his gold ring in cubic centimeters. He gets a glass in the shape of a rectangular prism with a
const2013 [10]
If you go to sc and slide to filter you’ll find one that solves the problem
7 0
3 years ago
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