Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56
fts
Now using Formula for time and range as
Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,
T is approximately equals to 4 sec.
Answer: 9-2 & -2-(-9)
Correct me if I'm wrong.
Step-by-step explanation:
We can create equations to solve this.
2.50p + 1.50m = 29.50
p + m = 15
Solve for a variable in the 2nd equation and use the substitution method to solve.
p + m = 15
Subtract p to both sides:
m = -p + 15
Plug in -p + 15 for m in the first equation.
2.50p + 1.50(-p + 15) = 29.50
Distribute:
2.50p - 1.50p + 22.50 = 29.50
Combine like terms:
p + 22.50 = 29.50
Subtract 22.50 to both sides:
p = 7
Now plug this into any of the two equations and solve for the other variable.
p + m = 15
7 + m = 15
Subtract 7 to both sides:
m = 8
So he purchased 7 pineapples and 8 mangos.
Answer:
Step-by-step explanation:
A rational number are numbers that can be expressed as as fraction. They can be expressed as a ratio of two integers. An irrational is quite the opposite. An irrational number cannot be expressed as a ratio of two integers.
Taking square root of two as an example;
√2 cannot be expressed as a ratio of two integers because the result will always be a decimal. If expressed as √2/1, it is still not a rational number because of the square root of 2 at the numerator. Square root of 2 is not an integer even though 1 is an integer.
Mark is wrong because √2 is irrational and it is irrational because it cannot be expressed as a ratio of two integers <em>not due to the fact that he can write it as a fraction.</em>
The equation gives the height of the ball. That is, h is the height of the ball. t is the time. Since we are looking for the time at which the height is 8 (h=8), we need to set the equation equal to 8 and solve for t. We do this as follows:
This is a quadratic equation and as it is set equal to 0 we can solve it using the quadratic formula. That formula is:
You might recall seeing this as "x=..." but since our equation is in terms of t we use "t-=..."
In order to use the formula we need to identify a, b and c.
a = the coefficient (number in front of)
= 16.
b = the coefficient of t = -60
c = the constant (the number that is by itself) = 7
Substituting these into the quadratic formula gives us:
As we have "plus minus" (this is usually written in symbols with a plus sign over a minus sign) we split the equation in two and obtain:
and
So the height is 8 feet at t = 3.63 and t=.12
It should make sense that there are two times. The ball goes up, reaches it's highest height and then comes back down. As such the height will be 8 at some point on the way up and also at some point on the way down.
