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Radda [10]
2 years ago
12

HELP PLEASEEEE IM BEGGING YOU

Mathematics
1 answer:
Alinara [238K]2 years ago
7 0

Answer:

40

3

9

70

6

7

10

2

42

8

Step-by-step explanation:

let's hope i didn't read naything wrong

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PLZ HELP DUE AT 12
aleksandrvk [35]

Answer:

The first one would be m^30n^20p^30  

And the second one would be a^2 / d^4  

Step-by-step explanation:

For 1, you have to multiply the inner exponents by the outer one so you get (m^12n^8) times (m^18n^12p^30). Then you mutiply the two together, so you add the exponents, where you get m^30n^20p^30.

For 2, since you're dividing, you have to subtract the exponents so you get a^2d^-4, but since you shouldn't have the negative you turn it into a^2 / d^4

Hope this helps :)

4 0
3 years ago
Suppose the juice boxes go on sale for $1.79 for the eight 4.23-ounce
lara [203]
Yes it does shegehehehavueheuwbuehwhwb
5 0
3 years ago
PLEASE HELP WITH THIS QUESTION​
Radda [10]

Answer:

The correct answer is Redbirds

P = 4/5 = 0.8

4 0
2 years ago
Find the key features of the equation and graph it. (Can you explain how to find them and not just the answers please)
Vadim26 [7]

Given a function in a table or in algebraic or graphical form, identify key features such as x- and y-intercepts; intervals where the function is increasing, decreasing, positive, or negative; relative maximums and minimums; symmetries; and end behavior. Use key features of an algebraic function to graph the function.

7 0
2 years ago
In a study of government financial aid for college​ students, it becomes necessary to estimate the percentage of​ full-time coll
ICE Princess25 [194]

Answer:

a) n = 1037.

b) n = 1026.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

​(a) Assume that nothing is known about the percentage to be estimated.

We need to find n when M = 0.04.

We dont know the percentage to be estimated, so we use \pi = 0.5, which is when we are going to need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 2.575\sqrt{\frac{0.5*0.5}{n}}

0.04\sqrt{n} = 2.575*0.5

(\sqrt{n}) = \frac{2.575*0.5}{0.04}

(\sqrt{n})^{2} = (\frac{2.575*0.5}{0.04})^{2}

n = 1036.03

Rounding up

n = 1037.

(b) Assume prior studies have shown that about 55​% of​ full-time students earn​ bachelor's degrees in four years or less.

\pi = 0.55

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 2.575\sqrt{\frac{0.55*0.45}{n}}

0.04\sqrt{n} = 2.575*\sqrt{0.55*0.45}

(\sqrt{n}) = \frac{2.575*\sqrt{0.55*0.45}}{0.04}

(\sqrt{n})^{2} = (\frac{2.575*\sqrt{0.55*0.45}}{0.04})^{2}

n = 1025.7

Rounding up

n = 1026.

6 0
3 years ago
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