V = 4/3πr^3
3V = 4πr^3
= r
If the dress is 90 dollars Nd it’s on sale Nd it’s 35%off how much is the dress
1 answer:
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Answer:
C. H0: µD = 0, HA: µD <0
Step-by-step explanation:
We assume that the paired sample data are simple random samples and that the differences have a distribution that is approximately normal. So for this case is better apply a paired t test.
A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.
Let put some notation
x=test value for pretest , y = test value for posttest
x: 66, 94, 87, 84, 76, 88
y: 75, 100, 93, 85, 75, 90
The system of hypothesis for this case are:
Null hypothesis:
Alternative hypothesis:
Because the difference D is defined as Pretest-Postest. And we want to see if the postets score is higher than the pretest with th training.
The first step is calculate the difference and we obtain this:
d: -9, -6, -6, -1, 1, -2
The second step is calculate the mean difference
The third step would be calculate the standard deviation for the differences, and we got:
The 4 step is calculate the statistic given by :
The next step is calculate the degrees of freedom given by:
Now we can calculate the p value, since we have a left tailed test the p value is given by:
The p value is lower than the significance level assumed , so then we can conclude that we can reject the null hypothesis. So we can say that the differences between Pretest and Posttest
are less than 0.
A keypad at the entrance of a building has 10 buttons labeled 0 through 9. What is the probability of a person correctly guessing a 9-digit entry code if they know that no digits repeat?
Answer:
the probability of a person correctly guessing a 9-digit entry code if they know that no digits repeat is 0.1
Step-by-step explanation:
We know that probability= number of required outcomes /number of all possible outcome.
From the given information;
the number of required outcome is guessing a 9-digit = 1 outcome
the number of all possible outcome = ¹⁰C₉ since there are 10 numbers and 9 number are to be selected.
Since there are only 9-digit that opens the lock;
the probability of a person correctly guessing a 9-digit entry code is
P = 0.1
The metric designators and trade sizes are for identification purposes only and are not actual dimensions, as pointed out in the note in table 300.1(C).
<h3>What are identification purposes?</h3>- For identification purposes, an acceptable ID MUST be issued by a Federal, State, County, or Municipal entity.
- For identification purposes, the single document must include the following criteria: photo, name, address (home/employer), date of birth, and be issued by a Federal, State, County, or Municipal entity.
[Refer The table 300.1(C) below.]
Therefore, the metric designators and trade sizes are for identification purposes only and are not actual dimensions, as pointed out in the note in table 300.1(C).
Know more about identification purposes here:
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The correct question is given below:
The metric designators and trade sizes are for identification purposes only and are not actual dimensions as pointed out in the note to Table?
