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andriy [413]
1 year ago
15

HELPPPP (x-y)^3-(y-x)^2

Mathematics
1 answer:
Nat2105 [25]1 year ago
8 0

Answer:

(x-y)(x-y)(x-y)= x²-yx+x²-yx-yx+y²-yx+y²

2x²-4yx+2y²

(y-x)(y-x)= y²-yx-yx+x²

y²-2yx+x²

-(y²-2yx+x²) = -y²+2yx-x²

2x²-4yx+2y²-y²+2yx-x²= x²-2yx+y²

or

(x−y−1)(x−y)² ≡ x³−x²+3xy²+2xy−y³−y²−3yx³

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Pls dont guess on it
yuradex [85]

Answer:

2(8a + 8)

Step-by-step explanation:

The easiest way to do this is to substitute <em>a</em> for a number. For example, let's just make things easy and make <em>a </em> = 1.

So, if a = 1, the expression 16a + 8 would be 16(1) + 8 = 24.

Let's find all the expressions that would also equal 24 if <em>a = </em>24.

Plug in 1 for <em>a</em> in each of the equations. You will find that 2(8a + 8) will not equal 24 if <em>a </em>equals 1.

2(8a + 8)

2(8(1) + 8

2(8 + 8)

2(16)

32

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Step-by-step explanation:

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3 years ago
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