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3 years ago

The discount price of a pair of pants is $42. What is the regular price?

Mathematics

2 answers:

maks197457 [2]3 years ago

5 0

What is the discount percentage

Rus_ich [418]3 years ago

3 0

You can’t answer that w/o a percent off

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What is 0.7 subtract 3

Irina18 [472]

Answer:

-2.3

Step-by-step explanation:

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2 years ago

If a dice is Rolled find the probibllity

goblinko [34]

Comeonshakeyourbodydothatcongaknowyoucantcontrolyourselfanylonger

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3 years ago

Write the Slope- Intercept equation of the line that passes through the given point and is perpendicular to the given line (0, -

damaskus [11]

Answer:

y+4=-3(x+0) or y=-3x-4

Step-by-step explanation:

so you have to make it in form y=mx+b

that would be y=1/3x-2/3

for a perpendicular line, you would need to find the opposite reciprocal of the slope

3/1 or 3 would be the reciprocal, so to make it opposite would be -3

So it would be y-y1 = m(x-x2)

fill it in with the coordinates (0,-4)

y+4=-3(x-0)

to get it to slope intercept form you have to simplify, and after that you get y=-3x-4

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3 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

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3 years ago

Write the equation of a line that has m = 2 and b = - 3.

MatroZZZ [7]

Answer:

Step-by-step explanation: y=2x−3

6 0

2 years ago