The discount price of a pair of pants is $42. What is the regular price?

Answer this please it’s for algebra 2

Sergeu [11.5K]

Part a)

P(junior) = (number of juniors)/(number total)

P(junior) = 235/705

P(junior) = 1/3 exactly

P(junior) = 0.33333 approximately

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Part b)

P(freshman and LG) = (number of freshman who have LG)/(number total)

P(freshman and LG) = 70/705

P(freshman and LG) = 14/141 exactly

P(freshman and LG) = 0.09929 approximately

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Part c)

n(junior) = number of juniors = 235

n(samsung) = number of people who have samsung = 274

n(junior and samsung) = number of juniors who have samsung = 93

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n(junior or samsung) = n(junior)+n(samsung)-n(junior and samsung)

n(junior or samsung) = 235+274-93

n(junior or samsung) = 416

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P(junior or samsung) = n(junior or samsung)/n(total)

P(junior or samsung) = 416/705 exactly

P(junior or samsung) = 0.59007 approximately

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Part d)

n(sophomore and apple) = number of sophomores who have apple

n(sophomore and apple) = 80

n(apple) = number of students who have apple

n(apple) = 261

P(sophomore | apple) = n(sophomore and apple)/n(apple)

P(sophomore | apple) = 80/261 exactly

P(sophomore | apple) = 0.30651 approximately

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Part e)

define the events

A = junior who has apple

B = junior who has samsung

C = person is a junior

n(A or B) = number of juniors who have apple or samsung

n(A or B) = n(A) + n(B) ... A and B assumed mutually exclusive

n(A or B) = 87+93

n(A or B) = 180

n(C) = 235

P( (Apple or Samsung) | Junior ) = n(A or B)/n(C)

P( (Apple or Samsung) | Junior ) = 180/235

P( (Apple or Samsung) | Junior ) = 36/47 exactly

P( (Apple or Samsung) | Junior ) = 0.76596 approximately

4 0

3 years ago

Solve for x: 4(x + 2) = 3(x − 2) A) −2 B)−4 C) −10 D) −14

BARSIC [14]

4(x+2)=3(x-2)

Multiply the first bracket by 4

Multiply the second bracket by 3

4x+8=3x-6

Move 3x to the left hand side, whenever moving a number with a letter the sign changes ( positive 3x to negative 3x)

4x-3x+8=3x-3x-6

x+8=-6

Move positive 8 to the right hand side

x+8-8=-6-8

x=-14

Check answer by using substitution method

Use x=-14 into both of the equations

4(-14+2)=3(-14-2)

-56+8=-42-6

-48=-48

Answer is -14- D)

6 0

3 years ago

Taylor needs to repair her car but cannot spend more than $260 for the repairs. The part needed for the repair will cost $80 and

Oksanka [162]

Answer: 6 hours

Step-by-step explanation:

Taylor cannot spend over $260.

Subtract the cost of the part needed for the repair:

= 260 - 80

= $180

$180 is left for fixing the car after buying the part.

As the labor costs $30 and now she cannot exceed $180 for labor, the total number of hours the mechanic can work is:

= 180 / 30

= 6 hours

6 0

2 years ago

In right triangle ABC, altitude CD is drawn to the hypotenuse. If

Free_Kalibri [48]

Answer:

A but I'm not so sure

Step-by-step explanation:

7 0

2 years ago

Greg and Erin start at the same point and begin running in different directions. Greg is running east at a speed of 7 miles per

AveGali [126]

Answer: The time at which the distance between the two is 150 miles is 1.3 hr.

Step-by-step explanation:

Step 1: Sketch the problem as shown in the attached image.

The problem can be solved using Pythagoras theorem since the sketch is a right angled triangle.

It follows the equation x² + y² = 15².

The distance covered by Greg is given by x mi, and that of Erin is given by y mi.

Step 2: To derive the distance covered by Erin and Greg, we use the formula Speed = distance ÷ time.

Which by cross-multiplying gives distance = speed × time.

Let time taken to cover the distance be t h.

Given that Speed of Erin is 9 mph and that of Greg is 7 mph.

Hence, distance covered by Greg, x = 7 × t = 7t.

Distance covered by Erin, y = 9 × t = 9t.

Step 3: Insert the terms x and y into the Pythagoras equation x² + y² = 15² and solve for time t.

(7t)² + (9t)² = 15²

49t² + 81t² = 225

(49 + 81)t² = 225

t² = 225/(49 + 81)

t² = 225/130

t² = 1.730769231

t = √1.730769231

t = 1.315587029

t = 1.3hr

Hence the time at which the distance between the two is 150 miles is 1.3 hr.

4 0

3 years ago