Answer:
The work done in stretching the spring is 8 lb.ft
Step-by-step explanation:
Given;
Applied force, F = 192 lb
extension of the spring, x = 3 ft
Determine the spring constant from the applied force and extension;
When the spring is stretched 6 inches beyond its natural length, the work done is calculated as follows;
x = 6 inches = 0.5 ft
Therefore, the work done in stretching the spring is 8 lb.ft
Based in your question where as ask on which of the following is the equivalent to x^2/xy^2 when y=0 and z=0 and based on my calculation and understanding the possible outcome of your equation will just result to zero but the answer is i think all of them
Parallel: line p with slope 2/5
Perpendicular: line n with slope -5/2
the other two would be neither.
Answer:
Domain- Interval Notation:
(
−
∞
,
∞
)
Set-Builder Notation:
{
x
|
x
∈
R
}
Range- Interval Notation:
(
−
9
,
∞
)
Set-Builder Notation:
{
y
|
y
>
−
9
}
Step-by-step explanation:
Horizontal asymptote- y=-9
0.024 is 2.4%
0.125 is 12.5%
0.05 is 5%
Showing the workMultiply 0.05 by 100 to convert to percent:
<span>0.05 × 100 = </span>5 %
0.5 is 50%
Showing the work - Multiply 0.5 by 100 to convert to percent:
0.5 × 100 = 50 %
Showing the work -multiply 0.024 by 100 to convert to percent:
0.024 × 100 = 2.4 %
