Use the number line below, where RS=5y+5, ST=2y+5, and RT=52. a. What is the value of y? b. Find RS and ST.
1 answer:
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Answer:
93.32% probability that a randomly selected score will be greater than 63.7.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a randomly selected score will be greater than 63.7.
This is 1 subtracted by the pvalue of Z when X = 63.7. So
has a pvalue of 0.0668
1 - 0.0668 = 0.9332
93.32% probability that a randomly selected score will be greater than 63.7.
Answer:
<u>Remove "x" and add</u>
-2 + 9 = 7
<u>Add "x" back</u>
7 -----> 7x
Note: When adding/subtracting problems like these remove "x" and then add/subtract normaly. When you get your answer put x back.