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9966 [12]
3 years ago
13

Solve each proportion algebraically. show you work. 9/15=m/25​

Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0

Answer:

m=15

Step-by-step explanation:

15 x 5 = 75 = 25 x 3

9 x 5=45 so 45/75 = 3m/75

45/3=15

m=15

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-5(-7,3) in y=mx+b form
kenny6666 [7]
Assuming -5 is m

y-3 = -5 (x + 7)
y - 3 = -5x - 35 
y = -5x - 33

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Mr. Huyck needs 8 gallons of punch for the school dance. How many<br> quarts of punch would he need?
koban [17]
32 bc eight times four equals 32
8 0
3 years ago
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Help its due tmmr and i dont under stand
const2013 [10]

If we want rice per person, that's

\dfrac{25}{3}

1a. Answer: 25/3

That's between 24/3 and 27/3 i.e. between

1b. Answer: 8 and 9


6 0
3 years ago
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Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
3 years ago
How to solve 2- 9/15​
Nezavi [6.7K]

Answer:

1 6/15

Step-by-step explanation:

15/15-9/15=6/15

8 0
3 years ago
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