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Inga [223]
3 years ago
8

Pls help I need a good grade I’ll brainlest

Mathematics
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

Step-by-step explanation:

A.

C.

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the answer is −2⋅(x+y)

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The sum of the measures of two alternate angles of two parallel lines is 210°. Find the two angles. (they are two answers) (one
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The measure of the angles are 105 degrees

<h3>How to determine the angles?</h3>

The sum of the angles is given as 210 degree

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4 0
2 years ago
Which polynomial identity will prove that 19 = 27 − 8? Difference of Squares Difference of Cubes Sum of Cubes Square of a Binomi
Lyrx [107]
The correct answer is:  [B]:  "Difference of Cubes". 
<span>__________________________________________________________

Explanation:
__________________________________________________________
Note that the equation/identity for the "difference of cubes" is expressed as:
___________________________________________________</span><span>_______

        " a</span>³ − b³ = (a − b)(a² + ab + b²) "  ; 
<span>__________________________________________________________

Note the given equation:  " 19 = 27 </span>− 8 " ;   →  (which is true). 
__________________________________________________________

       The "right hand side" of this equation:

            →  " 27 − 8 " ;  contains two numbers:  
         
            →  "27" and "8" ;  both of which are "cubes" ; 

            → that is:  ∛27 = 3 ;   ↔  3³ = 3 * 3 * 3 = 9 * 3 = 27 ;  <u><em>and</em></u>:

                               ∛ 8  = 2 ;  ↔  2³ = 2 * 2 * 2 = 4 * 2 = 8 ; 

            → <u>AND:</u>  "8" is being <u>SUBTRACTED</u> from "27" ; 

            →  (hence, the "difference of squares" polynomial identity); 

So:  given:     " 19 = 27  − 8 " ; 

→  Rewrite as:

        " 19 =  3³  − 2³ " ; 
_______________________________________________________
Now, consider the identity equation for the "difference of squares":

                          →   " a³ − b³ = (a − b)(a² + ab + b²) "  ; 
_______________________________________________________

Take:  " 19  =  3³  − 2³ " ; 

and rewrite as:  

→  3³  −  2³  = 19 ; 

So:   (a³ − b³) = 3³  −  2³ ; 

a = 3 ;  b = 2 ; 
___________________________________________________________
Plug in these values:

 " a³ − b³ = (a − b)(a² + ab + b²) " ; 

→   3³ − 2³  ≟  [3 − 2) [ 3² + (3*2) + 2² ]  ≟  19 ?  ; 

→  27 − 8   ≟  (1) (9 + 6 + 4) ≟  19 ?  ; 

→     19      ≟     (1) (15 + 4)   ≟  19 ?  ; 

→       19    ≟         (1) (19)     ≟  19 ?  ; 

→         19  ≟                19      ≟    19 ? ; 

→          19  =   19   =  19 !  Yes!  
___________________________________________________________
6 0
3 years ago
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