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3 years ago

15

Charlie runs ata speed of 3 yards per second. about how many miles per hour does charlie run?

1 answer:

DochEvi [55]3 years ago

8 0

(3 yard/sec) x (3,600 sec/hr) x (1 mile / 1,760 yard) =

(3 x 3,600 / 1,760) (mile/hour) = 6.136... mph (rounded)

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A golf player is trying to make a hole-in-one on the miniature golf green shown.

Flauer [41]

The path of the ball is an illustration of absolute equation.

The equation of the path is: $y =- \frac{12}7|x- 4.8| + 6.4$

The given parameters are:

$(h,k) = (4.8,6.4)$ --- the vertex (i.e. the point where the ball hits the wall)

$(x_1,y_1) = (2,1.6)$

$(x_2,y_2) = (7.6,1.6)$

An absolute function is represented as:

$y = a |x - h| + k$

Substitute $(h,k) = (4.8,6.4)$

$y = a |x - 4.8| + 6.4$

Substitute $(x_1,y_1) = (2,1.6)$ for x and y

$1.6 = a|2 - 4.8| + 6.4$

$1.6 = a|- 2.8| + 6.4$

Remove absolute bracket

$1.6 = 2.8a + 6.4$

Collect like terms

$2.8a = -6.4+1.6$

$2.8a =- 4.8$

Solve for a

$a =-\frac{4.8}{2.8}$

Simplify

$a =-\frac{12}{7}$

Substitute $a =-\frac{12}{7}$ in $y = a |x - 4.8| + 6.4$

$y =- \frac{12}7|x- 4.8| + 6.4$

Hence, the equation of the path is: $y =- \frac{12}7|x- 4.8| + 6.4$

See attachment for graph that models the path

Read more about absolute equations at:

brainly.com/question/2166748

5 0

2 years ago

Find the probability of rolling a 5 or greater on the first die and a 2 or greater on the second die

bekas [8.4K]

Answer:

The probability is 1/9

Step-by-step explanation:

The probability of rolling a 5 the first time is 1/6

The probability of rolling a number greater than 2

Numbers greater than 2 are 3, 4, 5, 6

So the probability of rolling a number out of these four is 4/6

So the probability of rolling a five for the first time and the probability of rolling a number greater than 2 the second time will be

1/6 * 4/6 = 4/36 = 1/9

6 0

3 years ago

Read 2 more answers

The sample space, S, for flipping a fair coin three times is shown

Ksenya-84 [330]

Answer: $\frac{7}{8}$

Step-by-step explanation:

Given

Sample space is $={HHH,THH,HTH,HHT,TTH,THT,HTT,TTT}$

There are 8 element in sample space which indicates the outcome of tossing a coin three times

Probability of obtaining at least one head $=1-P(\text{0 head})$

$P(\text{0 head})=P(\text{All tails})$

$P=1-\frac{1}{8}$

$P=\frac{7}{8}$

3 0

3 years ago

Russell has been training for the Emerald Valley Race. The first week he trained, he ran 5 days and took the same two routes eac

Ivahew [28]

In maths, Distance is described as the quantity of space between two points, and further calculation can be defined as follows:

Given Expression:

$5x + 2 = 30\\\\2(x + 5) = 30\\\\5(x + 2) = 30\\\\2x + 5 = 30$

To find:

distance=?

Solution:

$5\ days\ \begin{cases} & \text{ if } \text{before school 2 miles} \\ & \text{ if } \text{after school x miles} \end{cases}$

$\therefore 5(x+2)=30\\\\$

$\bold{5(x+2)=30}\\\\\bold{5x+10=30}\\\\\bold{5x=30-10}\\\\\bold{5x=20}\\\\$

$\bold{x=\frac{20}{4} }\\\\\bold{x=4}$

Therefore, the final answer is "4 miles".

Learn more:

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8 0

2 years ago

Read 2 more answers

Jobisdone [24]

Answer:

$16$ is the number of quarters and $14$ is the number of dimes

Step-by-step explanation:

we know that

$1\ dime=\$0.10$

$1\ quarter=\$0.25$

Let

x-----> the number of dimes

y------> the number of quarters

we know that

$0.10x+0.25y=5.40$ -----> equation A

$x+y=30$ ----Isolate the variable y

$y=30-x$ -----> equation B

Substitute equation B in equation A

$0.10x+0.25(30-x)=5.40$

$0.10x+7.5-0.25x=5.40$

$0.25x-0.10x=7.5-5.40$

$0.15x=2.1$

$x=14\ dimes$

Find the value of y

$y=30-x$

$y=30-14=16\ quarters$

therefore

$16$ is the number of quarters and $14$ is the number of dimes

8 0

3 years ago

Read 2 more answers