Formula for combinations:
(n!)/(r!(n-r)!)
For you, this is:
10!/(5!(10-5)!) = 10!/5!5! = (10•9•8•7•6•5•4•3•2)/(5•4•3•2)(5•4•3•2) = (10•9•8•7•6)/(5•4•3•2) = 30240/120=252 different ways.
Answer:
a.) Selecting two red balls (because there are more red balls than white)
OR
c.) Selecting 1 red ball and then 1 white ball (because there is also a chance of selecting a white ball after selecting a red ball)
(Not kinda sure)
<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
The answer will be -3.3. Hope this helps!
I cannot see the file attached. Can you type it in.
Use the answer as for photomath
