Answer:
B. i and iii
Step-by-step explanation:
There are mistakes in your question. But I solve this problem using the average mean of 15 because that is what is contained in the solution
Hypothesis
H0: u <= 15
H1: u > 15
Mean of x = 16.6
S = 2.22
Test statistic used is t test
16.6 - 15 / 2.22/√24
= 3.531
We find the critical value
Degree of freedom = 24-1 = 23
This is a one tailed test
Critical value = 1.714
We find p value using Ms excel T distribution function
= 0.000894
To make the decision
3.531 > 1.714 so we conclude that
I.) Reject null hypothesis
Iii) conclude an average if more than 15 hours is volunteered per month. So no need to institute the program.
The answer option Is B
Least common denominator of those two fractions is 15
Because 15 cant go any less
3 × 1 = 3 15 × 1 = 15
3 × 2 = 6
3 × 3 = 9
3 × 4 = 12
3 × 5 = 15
D = r t
384 = 640 * t
384/640 = t
.6 = t .6 of an hour
.6 hr * 60min/1 hr = 36 minutes (just in case it needs to be in minutes)
Answer:
350
Step-by-step explanation:
If there are 210 girls, then the number of boys is (210÷3)x7=350.
