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3 years ago

14

I need help NOW please and if you can, go to my other questions and try to help me out with those tooo!!!!!!!

1 answer:

kari74 [83]3 years ago

3 0

Answer:

B. y = sinx

Step-by-step explanation:

kasi yan ang "Tamang Sagot"

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The answer please.......

Vikki [24]

Answer:

c

Step-by-step explanation:

please give brainliest

5 0

3 years ago

Which expressions are equivalent. <br><br>PLEASE HELP ME !!! (photo given)

BabaBlast [244]

Answer:

$\frac{2^{5} }{6^{5} } =2^{5} 6^{-6}$

$=2^5\times (2^{-5} 3^{-5} )$

$=2^{5-5} 3^{-5}$

$=2^{0} 3^{-5}$

$=3^{-5}$

$OAmalOHopeO$

7 0

3 years ago

Read 2 more answers

The cost of a gallon of gas recently doubled. By what percent did it increase? A) 50% B) 100% C) 150% D) 200%

drek231 [11]

Hey there!

If a cost of a gallon recently doubled, then it increased by 50%. This is because half of 100% is 50% and it takes one more 50% to double.

Hope this helps you.
Have a great day!

5 0

3 years ago

In 2000 the population of a country reached 1 billion, and in 2025 it is projected to be 1.2 billion. (a) Find values for C an

Mice21 [21]

Answer:

(a) The value of C is 1.

(b) In 2010, the population would be 1.07555 billions.

(c) In 2047, the population would be 1.4 billions.

Step-by-step explanation:

(a) Here, the given function that shows the population(in billions) of the country in year x,

$P(x)=Ca^{x-2000}$

So, the population in 2000,

$P(2000)=Ca^{2000-2000}$

$=Ca^{0}$

$=C$

According to the question,

$P(2000)=1$

$\implies C=1$

(b) Similarly,

The population in 2025,

$P(2025)=Ca^{2025-2000}$

$=Ca^{25}$

$=a^{25}$ (∵ C = 1)

Again according to the question,

$P(2025)=1.2$

$a^{25}=1.2$

Taking ln both sides,

$\ln a^{25}=\ln 1.2$

$25\ln a = \ln 1.2$

$\ln a = \frac{\ln 1.2}{25}\approx 0.00729$

$a=e^{0.00729}=1.00731$

Thus, the function that shows the population in year x,

$P(x)=(1.00731)^{x-2000}$ ...... (1)

The population in 2010,

$P(2010)=(1.00731)^{2010-2000}=(1.00731)^{10}=1.07555$

Hence, the population in 2010 would be 1.07555 billions.

(c) If population P(x) = 1.4 billion,

Then, from equation (1),

$1.4=(1.00731)^{x-2000}$

$\ln 1.4=(x-2000)\ln 1.00731$

$0.33647 = (x-2000)0.00728$

$0.33647 = 0.00728x-14.56682$

$0.33647 + 14.56682 = 0.00728x$

$14.90329 = 0.00728x$

$\implies x=\frac{14.90329}{0.00728}\approx 2047$

Therefore, the country's population might reach 1.4 billion in 2047.

3 0

3 years ago

Please help math <br>question 1,2,3,4,5

kolezko [41]

The answers:

#1 C
#2 H maybe
#3 C
#4 H or J

6 0

3 years ago