Answer:
Market price = Rs. 6,000
Step-by-step explanation:
Given:
Cost price = R.s 4,000
Profit after discount = 20%
Discount = 20%
Find:
Market price
Computation:
Sales price = Cost price[1+Profit after discount]
Sales price = 4,000[1+20%]
Sales price = 4,800
Market price = Sales price[100/(100 - Discount)]
Market price = 4,800[100/(100 - 20%)]
Market price = Rs. 6,000
The equation modeling the height of the ball at time,t is given by h=-16t²+48t+6
<span>a. In how many seconds does the ball reach its maximum height?
Time taken for the ball to reach the maximum height will be given by:
h'(t)=-32t+48=0
finding the value of t we get:
32t=48
t=48/32
t=1.5 seconds
Thus the time taken for the ball to reach the maximum time is 1.5 seconds
b]</span><span> What is the ball’s maximum height?
The maximum height will be:
h(1.5)=-16(1.5)</span>²+48(1.5)+6
h(1.5)=42 fee
The horizontal distance traveled by the projectile is given as

where
V₀ = initial velocity, m/s
Note that
sin(2θ) = 2sinθ cosθ
Therefore, the horizontal distance traveled is

Because V₀ = 52 m/s, in order to travel a horizontal distance of 200 m, the correct equation to determine θ is
(52²/9.8) sin(2θ) = 200
or
275.92 sin(2θ) = 200
Answer: A
f(x) = −2x + 12, find f(x) when x = −3.
replace x = -3 then
f(-3) = (-2)(-3) + 12
= 6 + 12
=18
Answer is C) f(−3) = 18
f(p)=7/11p-10 Find f(77)
f(77) = 7/11 (77) - 10 (cancel out 77 and 11)
= 7 * 7 - 10
= 49 -10
=39
Answer is D) f(77) = 39