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Harrizon [31]
3 years ago
5

Choose the correct answer. Your bill from Acme is marked "3/12, net 30." The amount of the bill is $98.65. If you pay the bill w

ithin 12 days, how much should you tender?
a 95.69
b 96.57
c 97.44
Mathematics
2 answers:
xenn [34]3 years ago
5 0
I think it's B????? I may be wrong tho
r-ruslan [8.4K]3 years ago
4 0

Answer:

95.69

Step-by-step explanation:

this is the correct answer

brainlist if you woulds so kind

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How would you solve this problem 999 + 587 = 1000 + what = what ? How would this problem be solved
bija089 [108]

Answer:

2,586

Step-by-step explanation:

Add 1000+1000

2000

Since its 999 not 1000 subtract 1

1999

Now add 1 and subtract 1 from 587

Then add 2000 with 586

2,586

3 0
3 years ago
Read 2 more answers
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
In parallelogram ABCD, the length of BC=3x-1, CD=2x, and AD=x+5. Find the perimeter of ABCD
yarga [219]

Answer:

Step-by-step explanation:

BC=AD

3x-1=x+5

3x-x=5+1

2x=6

x=3

BC=3×3-1=8

CD=2x=2×3=6

perimeter=2(8+6)=2(14)=28

6 0
3 years ago
a light switch works 25% of the time, how many times does it not work if switched on 64 times in a week
alexira [117]
25% of 64 is 16
\frac{25}{100}  =  \frac{x}{64}  \\ x =  \frac{64 \times 25}{100}  =  \frac{1600}{100}  = 16
it will work properly 16 times
64 - 16 = 48
it will not work 48 times
hope this helps
7 0
3 years ago
A commercial fisherman is (less likely, equally likely, more likely) to need health insurance than a supermarket employee.
Talja [164]

Answer:

A commercial fisherman is  

EQUALLY LIKLEY

to need health insurance than a supermarket employee.

A person who smokes is  

MORE LIKLEY

to need health insurance than a nonsmoker.

An 18-year-old male college student is  

LESS LIKLEY

to need health insurance than a 72-year-old retired female.

5 0
2 years ago
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