Answer:
Tickets to sit on the bench (b) = 150
Tickets to sit on the lawn (l) = 200
Step-by-step explanation:
Tickets to sit on a bench (b)cost $75 each.
Tickets to sit on the lawn (l) cost $40 each
350 tickets had been sold
$19,250 had been raised through tickets sales
This forms a simultaneous equation:
b + l = 350 ... (i)
75b + 40l = 19,250 ... (ii)
Multiplying (i) by 40 and (ii) by 1 we get;
40b + 40l = 14,000 ... (i)
75b + 40l = 19,250 ... (ii)
Subtracting (ii) - (i) we get;
35b = 5250
b = 5250 ÷ 35 = 150
So there were 150 tickets to sit on a bench and 350 - 150 = 200 tickets to sit on the lawn.
Answer:
About 87$
Step-by-step explanation:
Yu take both salary amounts an divide by 52 since there are 52 weeks in a year and then find the difference between them
The distance between both lines is 2.24 units
Step-by-step explanation:
There is no straight method to find the distance between two lines. The distance can be found out by finding a point on one line and then finding the distance of that point from the other line. The y-coordinate of point is obtained by putting any value of x in equation . The x and y combined give us the point.
Given
We have to find the distance of this point from y=2x+5
The formula for finding distance of a point (x,y) from a line is:
A=2
B=-1
C=5
Putting the values in the formula
Rounding off will give: 2.24 units
The distance between both lines is 2.24 units
Keywords: Equations of lines
Learn more about distance in lines at:
#LearnwithBrainly
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
