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oksian1 [2.3K]
3 years ago
11

A community center is collecting blankets. Last year the center collected 81 blankets. This year they were able to collect 102 b

lankets. By what percentage did the community center increase the amount of blankets that they collected?
Very sorry I can't download any links you give me, sorry.
Mathematics
2 answers:
nekit [7.7K]3 years ago
7 0
The answer is 79.4%...
Paraphin [41]3 years ago
4 0

Answer:

79.4% (when rounding to the nearest tenth)

Step-by-step explanation:

81:102 = x:100

Cross multiple to get 8100=102x

Divide 8100 by 102

Round to the nearest tenth to get 79.4%

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Variable
umka2103 [35]

Answer:

true for number 1  and for number 2 It is not thats the wrong answer the real answer is 13 because 10 11 12 13

Step-by-step explanation:

7 0
3 years ago
Help with 30 please. thanks.​
Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

\displaystyle  y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}

And we want to show that:

\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}

Instead of differentiating directly, we can first square both sides:

\displaystyle y^2 = 3e^{2x} -4x + 1

We can find the first derivative through implicit differentiation:

\displaystyle 2y \frac{dy}{dx}  = 6e^{2x} -4

Hence:

\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}

And we can find the second derivative by using the quotient rule:

\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}

Substitute:

\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}

Simplify:

\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}

Combine fractions:

\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}

Simplify:

\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}

Simplify:

6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}

Q.E.D.

6 0
3 years ago
Simplify. Please and thank you.
Ivan
<span>Cancel <span>r2</span>
</span><span><span><span>(s4t)</span>/(</span><span>s<span>t3)</span></span></span>
2 <span>Use Quotient Rule: <span><span><span>xa/</span><span>xb</span></span>=<span>x^<span>a−b</span></span></span>
</span><span><span>s^<span>4−1</span></span><span>t^<span>1−3</span></span></span>
3 <span>Simplify <span>4−1</span> to 3
</span><span><span>s^3</span><span>t^<span>1−3</span></span></span>
4 <span>Simplify <span>1−3</span> to <span>−2</span>
</span><span><span>s^3</span><span>t^<span>−2</span></span></span>
5 <span>Use Negative Power Rule:<span><span>x^<span>−a</span></span>=<span>1/<span>xa</span></span></span>
</span><span><span>s^3</span>×<span>1/<span>t2</span></span></span>
6 <span>Simplify
</span><span><span>(s3)/(</span><span>t2)</span></span>
Done so the answer is a. then
8 0
3 years ago
Help solve #12 plz ​
nexus9112 [7]

Answer:

<h3>          The second:   f(-5) = 2</h3>

Step-by-step explanation:

x = -5

-5 < -4  and if x<-4 then  f(x) = - 2x - 8

so:

    f(-5) = - 2(-5) - 8 = 10 - 8 = 2

8 0
3 years ago
Please help solve for PQ.
DerKrebs [107]
This problem cannot be solved unless we are given figure NPQR is a rhombus.
In that case, then all sides are equal, meaning 
5x+16=9x-32
Solve for x
9x-5x=16+32
4x=48
x=12

Each side (including PQ) then equals 5x+16=5*12+16=76
8 0
3 years ago
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