When you triple the height of the box, it can hold (900 x 3) = 2,700 pieces.
Then triple its length, and it can hold (2,700 x 3) = 8,100 pieces.
Then triple its width, and it can hold (8,100 x 3) = 24,300 pieces.
When you triple the dimensions of a 3D object, it has 27 times its original volume. (900 x 27) = 24,300 .
<span>6x-7y=-84
7y = 6x + 84
y = 6/7(x) + 12</span>
Answer:
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Step-by-step explanation:
Y=1.5x+2
<h3>
<em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>1</u></em><em><u>)</u></em></h3>
y=1.5 (1) +2
y=1.5+2
y=3.5
<h3>
<em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>2</u></em><em><u>)</u></em></h3>
y=1.5(2)+2
y=3+2
y=5
<h3>
<em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>3</u></em><em><u>)</u></em></h3>
y=1.5 (3)+2
y=4.5+2
y=6.5
<h3>(x=4)</h3>
y=1.5 (4)+2
y=6+2
y=8
<h3>
<em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>5</u></em><em><u>)</u></em></h3>
y=1.5 (5)+2
y=7.5+2
y=9.5
<h2>
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Answer:
ΔV = 0.36π in³
Step-by-step explanation:
Given that:
The radius of a sphere = 3.0
If the measurement is correct within 0.01 inches
i.e the change in the radius Δr = 0.01
The objective is to use differentials to estimate the error in the volume of sphere.
We all know that the volume of a sphere
The differential of V with respect to r is:
dV = 4 πr² dr
which can be re-written as:
ΔV = 4 πr² Δr
ΔV = 4 × π × (3)² × 0.01
ΔV = 0.36π in³
Answer:
-38.4
Step-by-step explanation:
Multiply both sides by 6 to get rid of the /6 then you would get z alone
