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ZanzabumX [31]
3 years ago
12

ONLY ANSWER IF YOU KNOW

Mathematics
2 answers:
ElenaW [278]3 years ago
8 0
It’s literally not that hard all you have to do is quit being lazy and do it use your brain I don’t care if you delete this but it’s the truth
Ratling [72]3 years ago
7 0

Answer: how do we answer this I can’t draw on it

Step-by-step explanation:

You might be interested in
A) In a group of 60 students, 15 liked maths only, 20 liked science only and 5 did not like
Paladinen [302]

Part (i)

We have 60 students total, and 5 didn't like any of the two subjects, so that must mean 60-5 = 55 students liked at least one subject.

<h3>Answer: 55</h3>

=========================================================

Part (ii)

We have 15 who like math only, 20 who like science only, and 55 who like either (or both). Let x be the number of people who like both classes.

We can then say

15+20+x = 55

x+35 = 55

x = 55-35

x = 20

This means 20 people liked both subjects

<h3>Answer: 20</h3>

=========================================================

Part (iii)

There are 15 people who like math only, and 20 who like both. Therefore, there are 15+20 = 35 people who like math (and some of these people also like science)

<h3>Answer: 35</h3>

=========================================================

Part (iv)

We'll follow the same idea as the previous part. There are 20 people who like science only and 20 who like both subjects. That yields 40 people total who like science (and some of these people also like math).

<h3>Answer: 40</h3>

=========================================================

Part (v)

We'll draw a rectangle to represent the entire group of 60 students. This is considered the universal set. Inside the rectangle will be two overlapping circles to represent math (M) and science (S).

We'll have 15 go in circle M, but outside circle S to represent the 15 people who like math only. Then we have 20 go in circle S but outside circle M to show the 20 people who like science only. We have another copy of 20 go in the overlapped region between the circles. This is the 20 people who like both classes. And finally, we have 5 go outside both circles, but inside the rectangle. These are the 5 people who don't like either subject.

Note how all of the values in the diagram add up to 60

15+20+20+5 = 60

This helps confirm we have the correct values.

<h3>Answer: See the venn diagram below</h3>

3 0
3 years ago
HELP PLEASEEEEEEEEEeeeee
maks197457 [2]
Might have to experiment a bit to choose the right answer.

In A, the first term is 456 and the common difference is 10.  Each time we have a new term, the next one is the same except that 10 is added.

Suppose n were 1000.  Then we'd have 456 + (1000)(10) = 10456

In B, the first term is 5 and the common ratio is 3.  From 5 we get 15 by mult. 5 by 3.  Similarly, from 135 we get 405 by mult. 135 by 3.  This is a geom. series with first term 5 and common ratio 3.   a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.

Can you now examine C and D in the same manner, and then choose the greatest final value?  Safe to continue using n = 1000.





3 0
3 years ago
Quadrilateral ABCD is translated 2 units left and 3 units up to form quadrilateral A'B'C'D'
TiliK225 [7]
The answer would be
<span>B) 
A' (-8, 5)
B' (-8, 8)
C' (-5, 7)
D' (-4.5, 5)</span>
3 0
3 years ago
13. Which system of inequalities has no solution?
Anit [1.1K]

Answer:

Option A

Step-by-step explanation:

We have y < 2x - 4 and y > 2x + 1.

=> 2x - 4 > 2x + 1

=> -4 > 1

Since this inequality is false for all real values of x, there is no solution for the system of inequalities.

8 0
3 years ago
Determine the rate and the unit rate. $279 for 9 tickets. $18 for 6 volleyballs. 4 fouls in 20 minutes. 36 strikeouts in 54 inni
sergejj [24]
<span>The rate is the ratio and the unit rate is the rate when the denominator is 1.


$279 for 9 tickets.

=> rate = $279 / 9 tickets => unit rate = $ 31/ ticket

 $18 for 6 volleyballs.

=> rate = $ 18 / 6 volleyballs =>  unit rate = $ 3 / volleyball

4 fouls in 20 minutes.

=> rate = 4 fouls / 20 minutes => unit rate = 0.2 fouls / minute

36 strikeouts in 54 innings.

=> rate = 36 strikeouts / 54 innings => unit rate = 0.67 strikeouts / inning
</span>
4 0
3 years ago
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