Answer:
let the numbers be, x and x+1 ( as it is consecutive number the next number will have 1 more than the number )
sum = 41
so, x + ( x + 1 ) = 41
x + x + 1 = 41
2x + 1 = 41
2x = 41 -1 = 40
2x = 40
x = 40/2 = 20
x = 20
x + 1 = 20 + 1 = 21
so the consecutive numbers whose sum is 40 are, 20 and 21
hope this answer helps you.....
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Answer:The answer is 12
Step-by-step explanation:
I cheated
Answer:
−40+2n=−4n+8
−40+2n+40=−4n+8+40
2n=−4n+48
2n+4n=−4n+48+4n
6n=48
answer: n=8
Step-by-step explanation:
Answer: I can't view the model.
Step-by-step explanation:
