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Leto [7]
1 year ago
5

"eight times the difference of a number and three is sixty-four"?

Mathematics
2 answers:
morpeh [17]1 year ago
5 0

Answer:

the number would be 11

Step-by-step explanation:

8    ·    x - 3       =      64

________                 _          (divide both sides by 8)

8                                 8

x - 3  =   8

+ 3         + 3

x  = 11

(check:

11 - 3 = 8

8 x 8 = 64 )

blondinia [14]1 year ago
5 0

Hi student, let me help you out!

................................................................................................................................

        \bold{Let:}                                    \star

           \mathsf{s\:be\:the\:number}

The little phrase (eight times) tells us to multiply s times 8: \mathsf{8s}.

The phrase (the difference of) tells us to subtract 3 minus s: \mathsf{s-3}.

Now, the problem also tells us to multiply 8 times 3-s: \mathsf{8(s-3)}.

Notice I put parentheses around 3-s. This tells us to multiply 8 times both terms - 3 and -s.                                                  \star

Finally, this expression is 64. All of our hard work results in the following equation: ✨ \bigstar\underline{\boxed{\mathrm{8(s-3)=64}}}                                      \star

Hope this helped you out, ask in comments if any queries arise.

Best Regards!                                 \star

\star\bigstar\underline{\underline{\overline{\overline{\bold{Reach\:far.\:Aim\:high.\:Dream\:big.}}}}}\bigstar\star

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