Answer:
<em>A=3 and B=6</em>
Step-by-step explanation:
<u>Increasing and Decreasing Intervals of Functions</u>
Given f(x) as a real function and f'(x) its first derivative.
If f'(a)>0 the function is increasing in x=a
If f'(a)<0 the function is decreasing in x=a
If f'(a)=0 the function has a critical point in x=a
As we can see, the critical points may define open intervals where the function has different behaviors.
We have
Computing the first derivative:
We find the critical points equating f'(x) to zero
Simplifying by -6
We get the critical points
They define the following intervals
Thus A=3 and B=6
Answer:
8 = 4x OR 0 = 4x
Step-by-step explanation:
I not %100 sure or it could be 0 = 4x
EITHERONE
First, you should solve both equations for the same variable. Since the first one is already solved for y, solve the second equation for y as well.
6y = 2x + 6 Divide both sides by 6
y =
x + 1
You can see that both lines have a slope of
.
Lines that have the same slope are
parallel lines.
Answer:
380
Step-by-step explanation:
if you have 400 hundread you would subtract 5% from 400 amd you would get 380.
Here the denominators are quadratics , so we need to factorise them first
1/(x²-5x) +3/(x²+2x-35)
factorising x²-5x ,
here GCF is x, so taking x out we have
x(x-5)
factorising x²+2x-35 using AC method,
we find factors of -35 that add up to give 2
(x-5)(x+7)
Since we have x-5 common in both denominators, so lcd of the rational expression will be product of x(x-5)(x+7)
lcd is x(x-5)(x+7)
