<span><span>Solve <span>x5 + 3x4 – 23x3 – 51x2 + 94x + 120 </span></span>><span><span> 0</span>. </span></span><span>First, I factor to find the zeroes:<span><span>x5 + 3x4 – 23x3 – 51x2 + 94x + 120</span><span>= (x + 5)(x + 3)(x + 1)(x – 2)(x – 4) = 0</span></span><span>...so </span><span>x = –5, –3, –1, 2,</span><span> and </span>4<span> are the zeroes of this polynomial. (Review how to </span>solve polynomials, if you're not sure how to get this solution.)<span>To solve by the Test-Point Method, I would pick a sample point in each interval, the intervals being </span>(negative infinity, –5)<span>, </span>(–5, –3)<span>, </span>(–3, –1)<span>, </span>(–1, 2)<span>, </span>(2, 4)<span>, and </span>(4, positive infinity). As you can see, if your polynomial or rational function has many factors, the Test-Point Method can become quite time-consuming.<span>To solve by the Factor Method, I would solve each factor for its positivity: </span><span>x + 5 > 0</span><span> for </span><span>x > –5</span>;<span>x + 3 > 0</span><span> for </span><span>x > –3</span><span>; </span><span>x + 1 > 0</span><span> for </span><span>x > –1</span><span>; </span><span>x – 2 > 0</span><span> for </span><span>x > 2</span><span>; and </span><span>x – 4 > 0</span><span> for </span><span>x > 4</span>. Then I draw the grid:...and fill it in:...and solve:<span>Then the solution (remembering to include the endpoints, because this is an "or equal to" inequality) is the set of </span>x-values in the intervals<span> [–5, –3]<span>, </span>[–1, 2]<span>, and </span>[4, positive infinity]</span>. </span>
As you can see, if your polynomial or rational function has many factors, the Factor Method can be much faster.
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Answer:
false
Step-by-step explanation:
the relationship between lengths/dimensions and areas is that areas are created by multiplying 2 dimensions.
when you quadruple (×4) the dimensions, then the areas are growing with the square of the factor (×4×4 = ×16), because the factor goes twice into the multiplication : one time for every dimension involved.
so, quadrupling the dimensions would multiply the areas by 16.
The effect of Claudia's changing the height of of the triangle from 1 inch
to 3 inches is the option;
- The height of the triangle changed to three inches but the width remained 1 inch
<h3>Which option gives the effect of changing the height?</h3>
The given dimensions of the equilateral triangle Claudia added are;
Height of the triangle = 1 inch
Width of the triangle = 1 inch
The value Claudia typed in the Shape Height box = 3
Required:
What happened to the shape after she press Enter
Solution:
By entering 3 in the Shape Height box, changes the height of the
equilateral triangle to 3 inches but the width remains 1 inches
From a similar question posted online, the correct option is therefore;
- The height of the triangle changed to three inches but the width remained 1 inch
Learn more about triangles here:
brainly.com/question/16430835
<h3>
Answer: 5 cm</h3>
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Explanation:
Recall that the range for cosine is from -1 to 1, including both endpoints. The smallest cosine value is what we're after, since we want the height to be as small as possible (to allow the blade be closest to the table).
Effectively, this means we replace the cos(x) with -1 so that it's as small as possible. Then we compute to get:
20*cos(x)+25
20*(-1) + 25
-20 + 25
5
The height of the fan tip is 5 cm when it is the closest to the table.
Side note: On the flip side, the furthest away the fan tip can get is 20*(1) + 25 = 45 cm. Therefore, the range of y values is 
Answer: the surface area is 7,800
Step-by-step explanation:
