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erik [133]
3 years ago
12

Please help ASAP!!!!

Mathematics
1 answer:
horsena [70]3 years ago
7 0

Answer:

Step-by-step explanation:

(6,3) m = 1/2

b = y - (m)(x)

b = -3 - (1/2)(6)

b = -3 - 3

b = -6

y = 1/2x - 6

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Anettt [7]
4000 (4x10^3) times 400 (4x10^2) is equal to 16x10^5 ( 1,600,000)
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3 years ago
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I’m questioning whether or not the Gacha life thing matters or not.

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Read 2 more answers
Equivalent answers for 64 to the power of 2/3
madreJ [45]

Answer:

16

Step-by-step explanation:

Dealing with a fraction exponent on hand can be converted by using the fractional exponents rule where the fraction exponent is converted to something like this:

64^\frac{2}{3} = \sqrt[3]{64^{2}}\\

As you can see, the denominator of the fractional exponent is now the index of the radical. Here is a guide to know what goes where.

64^\frac{x}{y} = \sqrt[y]{64^{x}}

Both the original problem (64^2/3) and the converted formula can be put into a calculator.

<u>Simplify (if you want to)</u>

<u />\sqrt[3]{64^{2}}\\\sqrt[3]{4096}\\16<u />

<u />

64 to the power of 2/3 is 16.

5 0
3 years ago
What is the solution set to, "Katie wants to collect over 100 seashells. She already has 34 seashells in her collection. Each da
Anastaziya [24]

Answer:

Katie will collect more than 100 seashells in 5 and a half days.

Step-by-step explanation:

Katie already has 34 seashells in her collection.

Each day, she finds 12 more seashells on the beach.

Let x be the number of days Katie is collecting seashells.

In x days, she will collect 12x seashells.

In total, she will collect 34+12x seashells.

Katie wants to collect over 100 seashells, so

34+12x> 100

Solve this inequality. Subtract 34:

34+12x-34>100-34\\ \\12x>66\\ \\2x>11\\ \\x>5 \dfrac{1}{2}

Katie will collect more than 100 seashells in 5 and a half days.

3 0
4 years ago
Quadrilateral PQRS is transformed by translating it 6 units to the right and then rotating it 90° clockwise
Elina [12.6K]

Answer:

(y, -x -6)

Step-by-step explanation:

<em>The coordinates of PQRS is not given, however we'll assume the coordinates of PQRS to be (x,y)</em>

<em />

The first transformation: 6 units right

(x,y) -> (x + b, y)

Where b = 6

So, the new coordinates will be

(x + 6, y)

The second transformation: 90° clockwise

(x,y) -> (y,-x)

So, the new coordinates will be

(x + 6, y)-> (y, -x -6)

<em>Hence, the new coordinates of PQRS is (y, -x - 6)</em>

7 0
3 years ago
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